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OLEGan [10]
3 years ago
7

You are trying to cast four roles for a play. 12 actors try out, including sir Ian McKellen and Patrick Stewart. the director te

lls you that in order to bring the crowds, you must include at least one of sir Ian and Patrick in the cast. How many casts are possible?
Mathematics
1 answer:
Komok [63]3 years ago
8 0

Answer:

6,840 casts

Step-by-step explanation:

Assuming that every actor can play each of the 4 roles and that each role is different, the number of possible casts including at least one of sir Ian and Patrick is given by the total number of possible casts (permutation of 4 out of 12 actors), minus the number of casts without sir Ian and Patrick (permutation of 4 out of 10 actors):

n=\frac{12!}{(12-4!)} -\frac{10!}{(10-4)!}\\n=(12*11*10*9)-(10*9*8*7)\\n=6,840\ casts

There are 6,840 possible casts.

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Question is Incomplete;Complete question is given below;

Arla and kal both work in jobs they get paid by the hour in their first week on the job they each worked 40 hours and together there total earnings were $1300 in their second week on the job business was slow so arla worked 20 hours and kal worked 16 hours their total pool earning was $580 what is each persons hourly wage.

Answer:

The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.

Step-by-step explanation:

Let the hourly wage of Arla be 'x'

Also Let the hourly wage of Kal be 'y'

Now Given:

first week on the job they each worked 40 hours and together there total earnings were $1300

So we can say that;

40x+40y=1300   ⇒ equation 1

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Number of hours worked by Arla in second week = 20

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20x+16y=580   ⇒ equation 2

Now Multiplying equation 2 by 2 we get;

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Now Subtracting equation 3 from equation 1 we get;

(40x+40y)-(40x+32y)=1300-1160\\\\40x+40y-40x-32y=140\\\\8y=140

Now Dividing both side by 8 we get;

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40x+40y=1300\\\\40x+40\times17.5 =1300\\\\40x+700=1300\\\\40x=1300-700\\\\40x=600\\\\x=\frac{600}{40}\\\\x=\$15

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