All categories

3 years ago

Simplify the expression by combining any like terms.

Mathematics

2 answers:

algol133 years ago

7 0

Answer:

D. 5x+ y

1x + 4x = 5X

-6y + 7y = Y (1y)

Step-by-step explanation:

gavmur [86]3 years ago

5 0

D. 5x+ y

1x + 4x = 5X

-6y + 7y = Y (1y)

You might be interested in

How would you solve 7c + 12 = -4c + 78

Svetach [21]

Hello!

$7c+12 =-4c+78
 \\ 11c=66 \\ 
c=6$

First we will get the variable in the correct side.
add 4c to 7c.
Second thing you will do is subtract 12 from 78

Now, divide 66 by 11 and you'll be left with c=6

4 0

4 years ago

Read 2 more answers

Michael has constructed a device that fits on the end of a water hose. With this device, he can adjust the diameter of a tube co

Oduvanchick [21]

x
---- = 5 (solve for x)
0.6

x = 5(0.6)
x = 3

then....

3
----- = 15
0.2

your answer should be 15 ft per second.

hope this helps :)

3 0

4 years ago

Read 2 more answers

Suppose that T : R3 → R2 is given by:

Ad libitum [116K]

Answer: The required answers are

(a) T is proved to be a linear transformation.

(b) The matrix A such that T(x) = Ax is $\begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}$

Step-by-step explanation: We are given a linear transformation T : R³ → R² defined as follows :

$T(a,b,c)=(a,b).$

We are to

(a) prove that T is a linear transformation

and

(b) find a matrix A such that T(x) = Ax.

(a) Let s, t are any real numbers and (a, b, c), (a', b', c') ∈ R³.

Then, we have

$T(s(a,b,c)+t(a',b',c'))\\\\=T(sa+ta',sb+tb',sc+tc')\\\\=(sa+ta',sb+tb')\\\\=(sa,sb)+(ta'+tb')\\\\=s(a,b)+t(a',b')\\\\=sT(a,b,c)+tT(a',b',c').$

So, we get

$T(s(a,b,c)+t(a',b',c'))=sT(a,b,c)+tT(a',b',c').$

Therefore, T is a linear transformation.

(b) We know that B = {(1, 0, 0), (0, 1, 0), (0, 0, 1)} is a standard basis for R³ and B' = {(1, 0), (0, 1)} is a standard basis for R².

So, we have

$T(1,0,0)=(1,0)=1(1,0)+0(0,1),\\\\T(0,1,0)=(0,1)=0(1,0)+1(0,1),\\\\T(0,0,1)=(0,0)=0(1,0)+0(0,1).$

So, the matrix A such that T(x) = Ax will be given by

$\begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}$

Thus,

(a) T is proved to be a linear transformation.

(b) The matrix A such that T(x) = Ax is $\begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}$

4 0

3 years ago

In the equation y = kx, what does the variable k represent?

anyanavicka [17]

Answer:

I think it B but I really don't know cause need like an example

8 0

3 years ago

HELP QUESTION NUMBER THREE

yKpoI14uk [10]

Answer:

(-3,2) is the solution to the system of equation

Step-by-step explanation:

Here, we want to know the point that serves as a solution to the system of equation

We equate the y

-2x + 4 = -1/3x-1

Multiply through by 3

-6x + 12 = -x-3

-6x + x = -3-12

5x = 15

x = 15/5

x = 3

Substitute x into one of the y

y = -2(3) + 4

y = -6 + 4 = -2

So the solution is;

(3,-2)

8 0

3 years ago