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3 years ago

Need help answering C

Mathematics

1 answer:

notsponge [240]3 years ago

5 0

Answer:

gradient = -1/3

gradient of perpendicular= 3

y-2 = 3(x - 4)

Step-by-step explanation:

gradient of perpendicular * gradient = -1

You might be interested in

locate the point on the line segment A (3,-5) and B (13,-15) given that the point is 4/5 of the way from A to B. Show your work

rjkz [21]

Answer:

The coordinates of the point on the line segment between A (3 , -5) and B (13 , -15) given that the point is 4/5 of the way from A to B would be: (11 , -13)

Step-by-step explanation:

As the line segment has the points:

A(3, -5)

B(13, -15)

Let (x, y) be the point located on the line segment which is 4/5 of the way from A to B.

Using the formula

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

Here, the point (x , y) divides the line segment having end points (x₁, y₁) and (x₂, y₂) in the ratio m₁ : m₂ from the point (x₁, y₁).

As (x, y) be the point located on the line segment which is 4/5 of the way from A to B, meaning the distance from $A$ to $(x , y)$ is $4$ units, and the

distance from $(x , y)$ to B is 1 unit, as $5 - 4 = 1$ .

Thus

m : n = 4 : 1

Finding x-coordinate:

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$

$x=\frac{\left(3\right)\left(1\right)+\left(13\right)\left(4\right)}{4+1}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$x=\frac{3\cdot \:1+13\cdot \:4}{4+1}$

$x=\frac{55}{4+1}$ ∵ $3\cdot \:1+13\cdot \:4=55$

$x=\frac{55}{5}$

$\mathrm{Divide\:the\:numbers:}\:\frac{55}{5}=11$

$x=11$

Finding y-coordinate:

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

$y=\frac{\left(-5\right)\left(1\right)+\left(-15\right)\left(4\right)}{4+1}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$y=\frac{-5\cdot \:\:1-15\cdot \:\:4}{4+1}$

$=\frac{-65}{4+1}$ ∵ $-5\cdot \:1-15\cdot \:4=-65$

$=\frac{-65}{5}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$y=-\frac{65}{5}$

$y=-13$

The x-coordinate = 11

The y-coordinate = -13

Therefore, the coordinates of the point on the line segment between A (3 , -5) and B (13 , -15) given that the point is 4/5 of the way from A to B would be: (11 , -13)

7 0

3 years ago

TV−→− bisects ∠RTS. What is the relationship between ∠RTV and ∠STV?

kenny6666 [7]

Answer:

$RTV = STV$

Step-by-step explanation:

Required

Determine the relationship between RTV and STV

From the question, we understand that TV is a bisector of RTS at T;

This implies that, T divides RTS into two equal parts which are;

RTV and STV

Hence;

The relationship between RTV and STV is that, the are equal.

Mathematically;

$RTV = STV$

8 0

3 years ago

Find the Y-intercept and x-intercept of the line: 4x- 6y=21

zimovet [89]

Answer:

Step-by-step explanation:

4x-6y=21

divide by 21

$\frac{4x}{21} -\frac{6y}{21} =1\\or~\frac{x}{\frac{21}{4} } +\frac{y}{-\frac{7}{2} } =1\\x~intercept =\frac{21}{4} =5.25 \\y~intercept=-\frac{7}{2} =-3.5$