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chubhunter [2.5K]
3 years ago
9

Which angles are pairs of alternate exterior angles? Check all that apply.

Mathematics
2 answers:
Shalnov [3]3 years ago
8 0

Answer:

A & E

Step-by-step explanation:

An alternate exterior angle pair would have to be on the outside and be on opposite sides of the same line (like 5 and 11).

Vlada [557]3 years ago
6 0

first and before last one are my best guesses.

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Two times a number is equal to six less than three times the number
Mekhanik [1.2K]
2 times a number, x, is equal to 6 less than 3 times the number, x.

2x = 3x - 6
-1x = -6
x = 6

The number is 6.
8 0
3 years ago
I need help plz i dont get it and im trying to get my grade up
Ymorist [56]

Answer:

648

Step-by-step explanation:

(25 - 9 + 2)^2 / 3x6

= 108 x 6

= 608

follow BODMAS and you'll get it

If you would like to venture further, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

4 0
3 years ago
Read 2 more answers
Qual é o mdc de 340 e 728?
Diano4ka-milaya [45]
MDC and largest number that can divide two numbers while 
<span>340.728 2 </span>
<span>170.364 2 </span>
<span>85 182  </span>
<span>the highest numeropossivel that can divide two numbers are the same times 4 = 2.2</span>
7 0
3 years ago
Three times the difference of four times a number n and seven is no more than one
Sindrei [870]

Answer:

3x-4x7

Step-by-step explanation:

8 0
2 years ago
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
3 years ago
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