Answer:
The space available will vary between 800 GB (100%) and 400 GB (50%) of the total disks, depending on the RAID level.
The OS will handle the RAID as a single disk.
Explanation:
Each RAID level implements parity and redundancy in a different way, so the amount of disks used for this extra information will reduce the space available for actual storage.
Usual RAID levels are:
<u>RAID 0:</u> does not implement any redundancy or parity, so you will have available 100% of the total storage: 8 x 100 GB = 800 GB
<u>RAID 1:</u> Duplicates all the information in one disk to a second disk. Space is reduced in half: 400 GB
<u>RAID 5:</u> Uses the equivalent of 1 disk of parity data distributed evenly on each disk, meaning the space available is 
of the total disks: 
of 800 GB = 700 GB
Writting and reading the information on a RAID storage is handled by a raid controller, either implemented in hardware or software. The OS will "see" a single disk and will read or write information as usual.
I’d say both techies are correct.
Volatility, as applied in gasoline, is quantified by the tendency of the liquid to change to vapor at any given temperature (vaporize). This rate of change might be hard or easy, this depends on the temperature or the pressure. Technician B is also correct. RVP is defined and determined experimentally according to the ratio of the vapor volume to the liquid volume at 100 °F.
Answer:
Data transformation is the process of changing the format, structure, or values of data.
Explanation:
Answer:
7 raise to power 10
Explanation:
Since there are 4 possible ways to make memory chip and 3 possible ways to manufacture mother board, so for each machines we have 7 possible ways of configurations.
So total number of ways in which these machines can be configured is 7*7*7*...*7= 7raise to power 10 possible ways
Answer:
29
Explanation:
for n=28:
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Algorithm 1 performs f(n) = n2 + n/2 = 28*28 + 28/2 = 798
Algorithm 2 performs f(n) = 12*28 + 500 = 836
for n=29
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Algorithm 1 performs f(n) = n2 + n/2 = 29*29 + 29/2 = 855.5
Algorithm 2 performs f(n) = 12*29 + 500 = 848
so, for n=29, algorithm 2 will be faster than algorithm 1
