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nekit [7.7K]
2 years ago
8

Help pweeze this is due today :( I will give u brainliest just pweeze, I need this answer :(

Computers and Technology
1 answer:
IgorLugansk [536]2 years ago
8 0

Answer:

just go in a website and see why important to them

Explanation:

and why the share with more people

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True or False (type the entire word)
kozerog [31]

Answer:

True.

Explanation:

(Facts from Google): The answer is true because small data is defined as data that is small enough for human comprehension. Big data is data that comes in large chunks and is too large for traditional data processing. Small data is most likely all about finding the causation because it is understandable, and therefore can be read.

5 0
2 years ago
When the tcp\ip translates a network layer address into a data link layer address (after not finding an entry for the network la
Pavel [41]
When the network stack translates an IP address (network address) to a MAC address (data link address) it sends a broadcast using ARP to all devices on the subnet asking who has the specified IP address.  The device with that IP address will then respond with it's MAC address to the ARP message's source.

With this in mind the answer to your question would either be broadcast or ARP request depending on what you have been learning in class.
6 0
2 years ago
)How to extract a specific element of item in a list?
pogonyaev

Answer:

List items are usually accessed using the indexing operator.

Explanation:

Depends on the language, and what you mean with extracting? Do you mean accessing or removing?

3 0
3 years ago
Assume a TCP sender is continuously sending 1,090-byte segments. If a TCP receiver advertises a window size of 5,718 bytes, and
Arturiano [62]

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

4 0
3 years ago
Which of the following is an example of tangible property?
lyudmila [28]
<span>B an idea for an invention that your dad mentioned briefly but did not write down</span>
8 0
3 years ago
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