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kumpel [21]
3 years ago
12

Hugo is writing a coordinate proof to show that the midpoints of a quadrilateral are the vertices of a parallelogram. He starts

by assigning coordinates to the vertices of quadrilateral RSTV and labeling the midpoints of the sides of the quadrilateral as A, B, C, and D. Quadrilateral R S T V in a coordinate plane with vertex R at 0 comma 0, vertex S in the first quadrant at 2 a comma 2b, vertex T also in the first quadrant at 2 c comma 2 d, and vertex V on the positive side of the x-axis at 2 c comma 0. Point A is between points R and S, point B is between points S and T, point C is between points T and V, and point D is between points R and V. Enter the answers, in simplified form, in the boxes to complete the proof. The coordinates of point A are ( , ). The coordinates of point B are ( , ). The coordinates of point C are (2c, d) . The coordinates of point D are (c, 0) . The slope of both AB¯¯¯¯¯ and DC¯¯¯¯¯ is . The slope of both AD¯¯¯¯¯ and BC¯¯¯¯¯ is −bc−a . Because both pairs of opposite sides are parallel, quadrilateral ABCD is a parallelogram.

Mathematics
1 answer:
lesantik [10]3 years ago
8 0

Answer: Heres the answers!

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Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

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3 years ago
Help with this question
alexira [117]

Answer:

D

Step-by-step explanation:

It matches the most

3 0
2 years ago
Use function notation to represent the area of a circle whose circumference is 103 cm
Nataly_w [17]

Circumference of the circle =103 cm

i.e., C = 2 \pi r = 103

i.e., r = \frac{103}{2 \pi}


Area of the circle is given by

A = \pi r^2

A = \pi (\frac{103}{2 \pi})^2

A = \pi (\frac{10609}{4 \pi^2})

A =\frac{10609}{4 \pi}

Therefore, the area of the circle is: A =\frac{10609}{4 \pi}  cm^2

4 0
3 years ago
The diameter of this circle is 12 inches. The diameter of the smaller circle is 8 inches. find the area of the SHADED region.
kolezko [41]

Answer:

so you multiply 12 by 8 =96

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3 years ago
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IS -13 LESS THAN OR GREATER THAN 14
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It’s less than because it is a negative number
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