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3 years ago

Can someone help me with this question pls and thank you

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

5 0

X>2 is the answer I think

konstantin123 [22]3 years ago

3 0

Answer:

x>2

Step-by-step explanation:

Longer than two hours is >.

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2.What is the y-coordinate for the solution of the system of equations below

tino4ka555 [31]

the answer for this question is (C)3

5 0

3 years ago

How many 5/16's are in 1 & 7/8? *

Vilka [71]

Answer:

oh so for one get them to look alike.. sooo keep 5/16 and change 1 7/8 to

1 14/16 and then change it to 30/16 then simply compare 5 can go into 30 6 times soooooo it can go into 1 & 7/8 6 times

Step-by-step explanation:

5 0

3 years ago

Public health officials claim that people living in low income neighborhoods have different Physical Activity Levels (PAL) than

Naddika [18.5K]

Answer:

The z-score for this data is Z = -0.26.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

This is based on knowledge that in the U.S., the mean PAL is 1.65 and the standard deviation is 0.55.

This means that $\mu = 1.65, \sigma = 0.55$

A study took a random sample of 51 people who lived in low income neighborhoods and found their mean PAL to be 1.63.

This means that $n = 51, X = 1.63$

Using a one-sample z test, what is the z-score for this data

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{1.63 - 1.65}{\frac{0.55}{\sqrt{51}}}$

$Z = -0.26$

The z-score for this data is Z = -0.26.

4 0

3 years ago

The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 13.1 years; the standard devia

Ilia_Sergeevich [38]

Answer:

The probability between 16.1 and 17.6 years = 0.0214 years

The Estimate probability between 16.1 and 17.6 years = 2.14 years

Step-by-step explanation:

Step(i):-

Given the average of Population 13.1 years

The standard deviation of the Population = 1.5 years

Let 'x' be the random variable in Normal distribution

Given x = 16.1

$Z _{1} = \frac{x- mean}{S.D}$

$=\frac{16.1-13.1}{1.5}$

= 2

Z₁ = 2

Step(ii):-

Given x = 17.6

$Z_{2} = \frac{17.6- 13.1}{1.5}$

Z ₂= 3

Z₁ = 2 and Z ₂= 3 are both positive

The Estimate probability between 16.1 and 17.6 years

P( 16.1<x<17.6) = P( 2 < Z < 3)

= A(3) - A(2)

= 0.49865 - 0.4772 (from normal table)

= 0.0214

The probability between 16.1 and 17.6 years = 0.0214 years

= 0.0214 ×100

= 2.14 years

Final answer:-

The Estimate probability between 16.1 and 17.6 years = 2.14 years

8 0

3 years ago

Read 2 more answers

You catch an expected number of 1.51.5 fish per hour. You can catch a fish at any instant of time. Which distribution best chara

Illusion [34]

Answer:

The distribution is Poisson distribution

Step-by-step explanation:

From the question we are told that

An expected number of fish was caught per hour is 1.5

The distribution that best characterize the number of fish you catch in one hour of fishing is the Poisson distribution

This because generally the Poisson distribution is a distribution that shows the number of times a given event will occur within a defined period of time

6 0

3 years ago