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Komok [63]
3 years ago
13

What percent of 40.2 is 25.83?

Mathematics
1 answer:
Fynjy0 [20]3 years ago
4 0
25.83/40.2 is 0.643, or 64.3%
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what kind of growth model (pattern) is showen in the table x 1, 2, 3, 4, 5 y 5, 25, 125 ,635 ,3,125
Mandarinka [93]

Answer:

x= AP, y= GP

Step-by-step explanation:

x = 1, 2, 3, 4, 5 - difference in terms = 1, this is AP

y = 5, 25, 125, 625, 3125 - the ratio of increase= 5, this is GP

7 0
3 years ago
Find the next 3 terms. J30, J31, A31, S30
nikdorinn [45]

Answer:

Next 3 terms 031, N30, D31

Step-by-step explanation:

J30, J31, A31, S30

The above series represent the

first letter of the month and the days in it

J30= June which have 30 days

J31= July which has 31 days

A31= August which have 31 days

S30= September which have 30 days

30 days hath September, April, June and November. All the rest have 31 except February alone which has but 28 or 29 days

The next 3 terms of the series J30, J31, A31, S30 are 031, N30, D31

6 0
4 years ago
If each car has the same mass which car will require the longest time to come to a full stop
rosijanka [135]

Answer:

Car D

Step-by-step explanation:

Since the mass is the same, we need to depend on the speed. The lower the speed, the easier/faster to stop. The higher the speed, the longer it will take to come to a stop

5 0
4 years ago
What is the vertex of the parabola graphed
eimsori [14]

Answer:

Step-by-step explanation:

The vertex is either the highest point on the parabola or the lowest point. We have a positive parabola, so the vertex is a low point. It sits at (2, -4). Locate that point and see what I mean by the lowest point on the parabola.

5 0
4 years ago
The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate
marissa [1.9K]

Step-by-step explanation:

Continuous exponential growth model:

population = population(t = 0) \times e ^{ \alpha t}

Where α is the growth rate parameter.

So if t is the starting point and t+t1 is the point that population is doubled:

\frac{population(t + t1)}{population(t)}  = \frac{2 \times population(t)}{population(t)}  = 2 =  {e}^{ \alpha \times t1 }

So:

ln(2)  =  \alpha  \times t1

And as a result, t1, the time needed for the population to double at ANY given point is equal to:

t1 =  \frac{ ln(2) }{ \alpha }

3 0
4 years ago
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