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Nookie1986 [14]
3 years ago
7

Aubrey is painting a mural of an ocean scene. The triangular sail on a sailboat has a base of 4 feet and a height of 6 feet. Aub

rey will paint the sail using a special white paint. A can of this paint covers 10 square feet. How many cans of white paint will Aubrey need?
Mathematics
1 answer:
Wewaii [24]3 years ago
8 0
(1/2x4)x6
(2)x6
12/10
1.2

2 Cans because you cant buy .2 of a can

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(08.04 MC)
skelet666 [1.2K]

Answer:

292,968

Step-by-step explanation:

As we know,

Sum of a geometric sequence (S) = \frac{a(1-r^{n}) }{(1-r)}

where,

a = first term of sequence,

r = the constant ratio,

n = number of terms in sequence.

So, according to the question,

a = 3,

r = 5,

n = 8.

by substituting the values in the above formula, we get;

⇒ S=\frac{3(1-5^{8}) }{(1-5)}

⇒ 292,968

7 0
3 years ago
Melanie was training for a race. The line plot below shows the number of miles Melanie ran last week.
aliya0001 [1]
3/4+1/4=1
I’m not sure why you put the thing about Melanie there.
7 0
3 years ago
HELPPP ME PLEAASSEE.
siniylev [52]

Answer:

Betsy's calculations in Step 1 are correct because (8 + 18) gives 26. Betsy's calculations in Step 2 are incorrect because 3^4 doesn't give 12. If Betsy reaches her goal each year, she will have 2,106 customers 4 years from now.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

x^2-3x=x(x-3)

The x-3 terms cancel, leaving you with

\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}

and the limand is continuous at x=3, so we can substitute it to find the limit has a value of -1/18.

7 0
3 years ago
Help please 23 points will make brainliest
svlad2 [7]
It should be 78.54.
Double check that. 
Formula: V=πr2h/3
r2 is R squared 
8 0
3 years ago
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