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Anika [276]
3 years ago
12

Give an example of an equation that has no solution

Mathematics
2 answers:
mel-nik [20]3 years ago
4 0
2x + 5 = 2x - 3
2x - 2x = -3 - 5
0 = -8
Semmy [17]3 years ago
4 0

Answer: X² = -1

Step-by-step explanation: Let's take a look at the equation X² = -1. This equation has no solution in the real number system because any real number squared must be a positive. In other words, there is no real number x whose square is -1. However, we can expand our number system to include imaginary numbers but in the real number system, this would have no solution.

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AABC has vertices at A(1, -9), B(8,0), and C(9,-8).
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Check the picture below.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

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