Answer:
At least 75% of these commuting times are between 30 and 110 minutes
Step-by-step explanation:
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by 
.
In this question:
Mean of 70 minutes, standard deviation of 20 minutes.
Since nothing is known about the distribution, we use Chebyshev's Theorem.
What percentage of these commuting times are between 30 and 110 minutes
30 = 70 - 2*20
110 = 70 + 2*20
THis means that 30 and 110 minutes is within 2 standard deviations of the mean, which means that at least 75% of these commuting times are between 30 and 110 minutes
Vertical angles are formed when two lines intersect, and two angles that are on opposite sides of both lines.
The angles on the west side and the east side form two vertically opposite angles (commonly called vertical angles, but much less descriptive).
It is because the west angle is to the left of both lines, and the east angle is to the right of both lines.
Vertically opposite angles (vertical angles) are congruent. Therefore we can form the equation
110 = 5x
Divide both sides by 5 to get
110/5=22 = 5x/5 = x
or
x=22 degrees.
4/156 so
2/78 so
1/39 so approx. 2.5641%
Answer:
d) angle 6 is alternate interior angle to angle 3
e) angle 2 is alternate exterior angle to angle 7
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as
n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) = 
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
