Ask question

Ask question

All categories

4 years ago

11

What is the answer?

1 answer:

alexgriva [62]4 years ago

6 0

Answer:

Area = (2-3x)(2x+5)(x-1)

= -6x³-5x²+21x-10

Step-by-step explanation:

You might be interested in

Match each power of a power expression with its simplified expression.

VARVARA [1.3K]

Answer:

> $(4^6)^{-3}$ = $\frac{1}{4 ^ {18}}$

> $(4^{-3})^{-3}$ = $4 ^ 9$

> $(4^0)^{-9}$ = $4 ^0$

> $(-4^{-9})^2$ = $(-4) ^ {-18}$

Step-by-step explanation:

We have to expand the powers of each of them:

> $(4^6)^{-3}$ = $4^{(6 * -3)}$

= $4 ^ {-18}$

$(4^6)^{-3}$ = $\frac{1}{4 ^ {18}}$

> $(4^{-3})^{-3}$ = $4 ^ {(-3 * -3)}$

$(4^{-3})^{-3}$ = $4 ^ 9$

> $(4^0)^{-9}$ = $4 ^ {(0 * -9)}$

$(4^0)^{-9}$ = $4 ^0$

> $(-4^{-9})^2$ = $-4 ^ {( -9 * 2)}$

$(-4^{-9})^2$ = $-4 ^ {-18}$

8 0

3 years ago

Read 2 more answers

Write the fractions in order from least to greatest -3 3/4, -3 17/25, -3 13/20, -33/5

Natali [406]

3 17/25 3 13/20 3 3/5 3 3/4

7 0

3 years ago

A flower pot weighing 3 newtons is sitting on a windowsill 10 meters from the ground what is its potential energy

krek1111 [17]

Answer:

30 J

Step-by-step explanation:

W = mg = 3 N

h = 10 m

Potential Energy = mgh = 3*10 = 30 J

5 0

3 years ago

an initial population of 700 trout increases at an annual rate of 22%. Which exponential function models the trout population?

REY [17]

Answer:

$y=700(1.22)^{x}$

Step-by-step explanation:

Let

y-----> the trout population

x----> the time in years

we know that

$22\%=22/100=0.22$

$y=700(1+0.22)^{x}$

$y=700(1.22)^{x}$ ----->exponential function that models the trout population

7 0

3 years ago

50 km/h east is an example of

gladu [14]

Acceleration is the answer

3 0

2 years ago