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Fofino [41]
3 years ago
11

Which would be the best sample for

Mathematics
2 answers:
vesna_86 [32]3 years ago
4 0
B because it’s a random sample and it’s not biased
Ksivusya [100]3 years ago
3 0

Answer:

It would either be B or C. More than likely it would be B.

Step-by-step explanation:

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A photo is 4 inches wide. It is placed inside a frame with a border that is x inches wide. The total width of the photo and the
Anna [14]
4 + 2x = 7
2x = 7 - 4 = 3
x = 3/2 = 1.5 inches
5 0
3 years ago
Korie randomly selects a number from the numbers shown below. 54, 60, 11, 0, 5, 7, 20 What is the probability that the number sh
grandymaker [24]

Answer:

there is a greater chance that she selects a even number because there are 4 even numbers and 3 odd numbers

8 0
3 years ago
The swim team has 41 people on their team they need new swim gear the swim caps cost $5 and the swim suit cost $ 16 dollars how
IRISSAK [1]

Answer:

The money they will have to pay is <u>$861</u>.

Step-by-step explanation:

Given:

The swim team has 41 people on their team.

They need new swim gear the swim caps cost $5 and the swim suit cost $16.

Now, to find the money they will have to pay.

Number of people on the swim team = 41.

Cost of swim caps = $5.

Cost of swim suit = $16.

Now, to get the total money they will have to pay:

<u><em>Number of people on the swim team× (cost of swim caps + cost of swim suit)</em></u>

=41\times (5 +16)

=41\times 21

=\$861.

Therefore, the money they will have to pay is $861.

7 0
3 years ago
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
How old is the 7th person that walked in?
mario62 [17]
7th person that walked in would be 66 years old
7 0
3 years ago
Read 2 more answers
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