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zvonat [6]
3 years ago
6

Como habra aprendido su oficio quien se ocupa de transplantar los plantines?

SAT
1 answer:
valina [46]3 years ago
4 0

Answer:

Generalmente, las personas que se encargan de transplantar plantines con semillas cultivadas son jardineros. Estas personas se encargan de cuidar plantas, semillas, vegetales y todos los componentes de un jardín, sea dentro de una casa o en un parque público.

Estas personas no requieren de un estudio de grado para poder ejercer su actividad laboral: generalmente, estas personas adquieren su oficio a través de la práctica, sea empezando como ayudante de un jardinero en actividad o a través de cursos de aprendizaje.

En cualquier caso, es una profesión que requiere de la actividad constante para adquirir los conocimientos necesarios que permitan perfeccionarse en el uso de las herramientas y el conocimiento de las técnicas que permitan un correcto cuidado de jardines, parques y plantaciones. Obviamente, también el estudio es importante, pero suele quedar en un segundo plano, por detrás de la experiencia laboral y la práctica en campo.

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This is a major spiral arm of the milky way which is neighboring the minor arm upon which our solar system is located. It is mor
Keith_Richards [23]

Answer: Orion Arm

Explanation:

We live in a seemingly nondescript neighborhood in the Milky Way galaxy, in a small spiral arm called the Orion Arm.

THANK you and have a great day!

3 0
3 years ago
Which process involves a decrease in temperature?
Bond [772]
Boiling an egg will decrease the temperature during the process
4 0
3 years ago
Which of the following is the most likely reason the writers of the constitution did not define american citizenship
Lesechka [4]
B.They do not want to limit the right of individuals.
3 0
3 years ago
Let A and B be events with P(A) = 0.61 and P(A ∩ B) = 0.39. For what value of P(B) will A and B be independent?
timofeeve [1]

Answer:

P(B) = 0.64

Explanation:

Given

P(A) = 0.61

P(A\ n\ B) = 0.39

Required

Determine P(B)

If A and B are independent, then:

P(A\ n\ B) = P(A) * P(B)

Substitute values for P(A) and P(A n B)

0.39 = 0.61 * P(B)

Make P(B) the subject

P(B) = \frac{0.39}{0.61}

<em />P(B) = 0.64<em> --- approximated</em>

7 0
3 years ago
A photographic stop bath contains 160ml of pure acetic acid.
NeTakaya

Answer:

Solving for the Percent by Volume

The v/v concentration of acetic acid in the stop bath is 24.6%.

Explanation:

To answer the question, we need to identify certain information stated in the question. Let us write down what’s given:

Volume of solute = 160 mL

Volume of solution = 650 mL

Next, we need to determine what is required, in this case, the percent by volume. Now, let us look at the formula:

v/v concentration = (solute volume / volume of the solution) * 100

Solution:

Percent by Volume = (160 / 650) * 100

Percent by Volume = 0.2461538461538462 * 100

Percent by Volume = 24.61538461538462

Rounded off = 24.6%

Therefore, the final answer is 24.6%

Explanation:

7 0
2 years ago
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