Suppose that the demand equation for a certain item is 1p+1x2−160=0. evaluate the elasticity at 65:
1 answer:
Price elasticity is defined as 
.
Here, the question has omitted to define variables, so we will ASSUME
p=price
x=variable,
and we're given
p+x^2-160=0
We calculate
by implicit differentiation with respect to p:
1+2x (dx/dp)=0
=>
E(x)=(dx/dp)=-1/(2x)
Therefore the price elasticity at x=65 is
E(65)=1/(2*65) =-1/130 (approximately -0.00769)
Here, the question has omitted to define variables, so we will ASSUME
p=price
x=variable,
and we're given
p+x^2-160=0
We calculate
1+2x (dx/dp)=0
=>
E(x)=(dx/dp)=-1/(2x)
Therefore the price elasticity at x=65 is
E(65)=1/(2*65) =-1/130 (approximately -0.00769)
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Answer:
Step-by-step explanation:
Let be the greater number and
be the smaller number. We know that their difference is 15, so we have
Then, we have the following information: if we add twice the greater (2x) and 8 (2x+8), the result is 3 times the lesser (3y) minus four (3y-4). So, we have
So, we have the follwing system:
From the first equation, we can derive , and substitute this expression in the second equation to get
Substitute this value for y in the first equation to get