Suppose that the demand equation for a certain item is 1p+1x2−160=0. evaluate the elasticity at 65:
1 answer:
Price elasticity is defined as 
.
Here, the question has omitted to define variables, so we will ASSUME
p=price
x=variable,
and we're given
p+x^2-160=0
We calculate
by implicit differentiation with respect to p:
1+2x (dx/dp)=0
=>
E(x)=(dx/dp)=-1/(2x)
Therefore the price elasticity at x=65 is
E(65)=1/(2*65) =-1/130 (approximately -0.00769)
Here, the question has omitted to define variables, so we will ASSUME
p=price
x=variable,
and we're given
p+x^2-160=0
We calculate
1+2x (dx/dp)=0
=>
E(x)=(dx/dp)=-1/(2x)
Therefore the price elasticity at x=65 is
E(65)=1/(2*65) =-1/130 (approximately -0.00769)
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Answer:
B. 41.8° is the correct answer
Step-by-step explanation:
We are given that,
Length of Eduardo's flight path = 273 miles
Length of Paul's flight path = 357 miles
Distance between their destinations = 238 miles.
Now, using the law of cosines, we get,
i.e.
i.e.
i.e.
i.e.
i.e.
i.e. θ = 41.8°
Hence, the angle between their flight paths is 41.8°.