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ser-zykov [4K]
3 years ago
7

Suppose that the demand equation for a certain item is 1p+1x2−160=0. evaluate the elasticity at 65:

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0
Price elasticity is defined as \frac{\Delta(quantity)}{\Delta(price)}.

Here, the question has omitted to define variables, so we will ASSUME
p=price
x=variable,
and we're given
p+x^2-160=0

We calculate
\delta{x}/\delta{p} by implicit differentiation with respect to p:
1+2x (dx/dp)=0
=>
E(x)=(dx/dp)=-1/(2x)

Therefore the price elasticity at x=65 is
E(65)=1/(2*65) =-1/130 (approximately -0.00769)

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Which is another way to check the sum of 104 + 34 + 228 + 877?
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The answer is D. 877 + 228 + 34 + 104

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A toy car accelerates from rest to a velocity of 4.3 m/s. It does this over a time of 4 seconds. What is the car's acceleration?
Oxana [17]

Answer:

it will be 8.3 seconds try to add

4 0
3 years ago
Susan paid $15.84 for a 7.48 - kg bag of dog food. A few weeks later, she paid $16.58 for a 7.94 - kg bag at a different store.
barxatty [35]

The unit price for the 7.48 is $2 kg per bag and the unit price for the 7.94 is $2 per kg bag, there is no difference in unit rates of both the bag.

<h3>What is unit rate?</h3>

A unit rate means a rate for one of something.

Given that, Susan paid $15.84 for a 7.48 kg bag of dog food. A few weeks later, she paid $16.58 for a 7.94 kg bag at a different store.

15.48/7.48 = $2/kg

16.58/7.94 = $2/kg

Hence, there is no difference in between both the bags, hence either of them are better.

For more references on unit rates, click;

brainly.com/question/11258929

#SPJ1

4 0
1 year ago
A box contains eight cards numbered 2, 3, 4, 5, 6, 7, 8, 9. One card is selected at random and replaced. What is the probability
Archy [21]

Answer:

1/2

Step-by-step explanation:prime numbers ={2,3,5,7}

likelihood of prime numbers =number of prime numbers /all numbers

                                                  =4/8 , 4 divides itself once and 4 divides 8 twice.

                                                  =1/2

7 0
3 years ago
The random variable X~(30,2^2) <br> Find p(X&lt;33) <br> Find p(X&gt;26)
Ostrovityanka [42]

Answer:

i) P(X<33)  = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable  X = 33

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-30}{2} = 1.5 >0

P(X<33) = P( Z<1.5)

              = 1- P(Z>1.5)

             = 1 - ( 0.5 - A(1.5))

             = 0.5 + 0.4232

  P(X<33)  = 0.9232

<u>Step(iii) :-</u>

Given that the random variable  X = 26

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-26}{2} = 3.5 >0

P(X>26)  = P( Z>3.5)

              = 0.5 - A(3.5)

              = 0.5 - 0.4990

             = 0.001

P(X>26) = 0.001

5 0
3 years ago
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