3 years ago

Classify the system of equations -3x=3-y 3+y=3x-2

1 answer:

wel3 years ago

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Change the equations into slope intercept form
y = 3x + 3
y = 3x - 5

Both slopes of the lines are 3. Therefore, the lines are parallel

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The simplified equation of $(x - 10)^2 + (y- 6)^2 = 4^2$ is $y = 6+ \sqrt{16 - (x - 10)^2}$

<h3>How to determine the simplified equation?</h3>

The complete question is added as an attachment

The equation is given as

$(x - 10)^2 + (y- 6)^2 = 4^2$

Subtract (x - 10)^2 from both sides

$(y- 6)^2 = 4^2 - (x - 10)^2$

Evaluate 4^2

$(y- 6)^2 =16 - (x - 10)^2$

Take the square root of both sides

$y- 6= \sqrt{16 - (x - 10)^2}$

Add 6 to both sides

$y = 6+ \sqrt{16 - (x - 10)^2}$

Hence, the simplified equation of $(x - 10)^2 + (y- 6)^2 = 4^2$ is $y = 6+ \sqrt{16 - (x - 10)^2}$

Read more about simplified equation at:

brainly.com/question/723406

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