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stiks02 [169]
3 years ago
9

Mike has g green marbles and y yellow marbles. Tina keeps losing her marbles. She has half as many yellow and 3 less green marbl

es than Mike. Write an expression for Tina's marbles.

Mathematics
1 answer:
madreJ [45]3 years ago
5 0

there you go ............

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Answer:

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Step-by-step explanation:

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Black_prince [1.1K]
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A student wants to survey the sophomore class of 200 students about whether the school should require uniforms. A
Fittoniya [83]

Answer: C

Step-by-step explanation:

<u>Given:</u>

Sample size (n) = 50

x = 12

\widehat{\mathbf{p}}=\frac{\mathbf{x}}{n}=\frac{12}{50}=0.24

Confidence level = 90%

α = 1 − 0.90 = 0.10

α/2 = 0.05

\text { Critical value }\left(z_{c}\right)=z_{\frac{\alpha}{2}}=z_{0.05}=1.6449

(from standard normal table)

90% Confidence interval is,

\begin{aligned}&\text { Confidence interval }=\widehat{\mathbf{p}} \pm z_{c} \times \sqrt{\frac{\hat{\mathbf{p}}(1-\hat{\mathbf{p}})}{n}} \\&\text { C. I }=0.24 \pm 1.6449 \times \sqrt{\frac{0.24(1-0.24)}{50}} \\&\text { C. I }=0.24 \pm 1.65 \times \sqrt{\frac{0.24(1-0.24)}{50}}\left\end{aligned}

Therefore, 90% confidence interval for the true proportion of sophomores who favour the adoption of uniforms is C

6 0
3 years ago
Find integrate (1/(xsqrt(1+(lnx)^2)),1,e,x) ...?
prohojiy [21]
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as 

<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>

<span>Next, complete the square. </span>

<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>

<span>Also, for the x in the numerator </span>

<span>x = x + 1/2 - 1/2. </span>

<span>So </span>

<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>

<span>Integrate term by term to get </span>

<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>

<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>

<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>

<span>= 2 √(x) ln(x) - √(x) + C. </span>

<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>

<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>

<span>= arctan(e^x) + C.</span>
4 0
4 years ago
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