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3 years ago

write a short note to a friend explaining when to reverse the inequality when you are solving an inequality

1 answer:

3 0

You reverse the inequality when you divide both sides by a negative number.
example:
-5x>45 (you divide both sides here by -5 to get the value of x)
answer:
x<9 (notice inequality has been has been reversed)

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Convert 18 centimeters per second to meters per hour.<br> hint: 1 m = 100 cm

denis-greek [22]

Answer:

The answer to your question is 648 m/h

Step-by-step explanation:

$\frac{18 cm}{s} \frac{1 m}{100 cm} \frac{3600 s}{1 h}$

$\frac{(18)(1)(3600)}{(1)(100)(1)}$

$\frac{64800}{100}$

= 648 m/h

3 0

3 years ago

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Question 2 (20 points)

almond37 [142]

The answer is:

7 miles

5+2=7

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3 years ago

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) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

What is the value of x?

lorasvet [3.4K]

Answer:

x=9

Step-by-step explanation:

We can use similar triangles and ratios. Put the small triangle side over the large triangle side.

9cm 3x -20

---------- = ---------------- We need to add the sides to get to the larger triangle

72+9 cm 3x-20 + 56

We can cross multiply to solve

9 * (3x-20+56) = (72+9) * (3x-20)

Simplify

9*(3x+36) = 81*(3x-20)

Distribute

27x +324 = 243x -1620

Subtract 27x from each side

27x-27x +324 = 243x-27x -1620

324 = 216x-1620

Add 1620 to each side

324+1620 = 216x

1944 = 216x

Divide each side by 216

1944/216 = 216x/216

9=x

6 0

3 years ago

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A taxi ride costs p40.00 for the first 500 meters and each additional 300 meters or a fraction there of adds p3.50 to the fare.u

Zarrin [17]

The function which represents the taxi fare in terms of distance d in meter is f(d) = 3.50 × $\frac{d-500}{300}$ + 40 .

According to the question,

For first 500 meters cost is 40.00 and For each additional 300 meters cost is 3.50 .

Let, the total distance of taxi ride = d meters

Now, representing the equation of taxi fare in terms of distance when distance is less than 500

taxi fare = 3.50 × $\frac{d-500}{300}$ + 40

∴ f(d) = 3.50 × $\frac{d-500}{300}$ + 40

To know more about functions refer below link: brainly.com/question/12431044

#SPJ4

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1 year ago