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Mkey [24]
3 years ago
15

How to get out of compatibility mode in word?

Computers and Technology
1 answer:
fomenos3 years ago
5 0
Compatibility mode is so older or different versions of word all look the same regardless of its current version.  So a lot of features you see in compatibility mode will be unavailable unless you upgrade.  If you upgrade though be sure to uninstall the older version first.  I hope this helped!!! Good Luck! :)
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If you don’t have a paper copy of the FAFSA form, how else can you fill it out?
Ronch [10]
Go on your school computer, and find a copy of the form. Then print it from the school printer.
3 0
3 years ago
Read 2 more answers
If a while loop iterates forever,what is the most likely cause?
miv72 [106K]

Answer:

Runtime error probably. The program won't make it past the while loop in the code.

5 0
2 years ago
Why people get addited to mobile and by playing games​
nadya68 [22]
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4 0
3 years ago
You have purchased a printer that has the capability to print in duplex mode so that users can print on both sides of a sheet of
fiasKO [112]

If you have purchased a printer that has the capability to print in duplex mode so that users can print on both sides of a sheet of paper. However, when users try to use this capability when they send a print job, documents are still printed on only one side. Then there might be a problem with (d) THE DUPLEX MODE NEEDS TO BE ENABLED ON THE DEVICE SETTINGS TAB IN THE PRINTER'S PROPERTIES.

Explanation:

  • If the duplex mode isn't enable on the printer setting, then the printer is still going to read that the output should come in a single page and not in the duplex mode.
  • When facing such a problem, the user should go to the "Device Settings" tab in the printer properties and change the required settings to print according to the users needs.

7 0
4 years ago
Write a function with this prototype:
sp2606 [1]

Answer:

Following are the code to this question:

#include <iostream> //defining header file  

using namespace std;

void numbers(ostream &outs, const string& prefix, unsigned int levels); // method declaration

void numbers(ostream &outs, const string& prefix, unsigned int levels) //defining method number

{

string s; //defining string variable

if(levels == 0) //defining condition statement that check levels value is equal to 0

{

outs << prefix << endl;  //use value

}

else //define else part

{

for(char c = '1'; c <= '9'; c++) //define loop that calls numbers method

{

s = prefix + c + '.'; // holding value in s variable  

numbers(outs, s, levels-1); //call method numbers

}

}

}

int main() //defining main method

{

numbers(cout, "THERBLIG", 2); //call method numbers method that accepts value

return 0;

}

Output:

please find the attachment.

Explanation:

Program description:

  • In the given program, a method number is declared, that accepts three arguments in its parameter that are "outs, prefix, levels", and all the variable uses the address operator to hold its value.
  • Inside the method a conditional statement is used in which string variable s and a conditional statement is used, in if the block it checks level variable value is equal to 0. if it is false it will go to else block that uses the loop to call method.
  • In the main method we call the number method and pass the value in its parameter.  

5 0
3 years ago
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