Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
Answer:
Explanation: The first thing to calculate is what IP addresses are used by the largest LAN. Because the LAN has 100 hosts, 7 bits must be left for host bits.
Explanation:
Explanation: The first thing to calculate is what IP addresses are used by the largest LAN. Because the LAN has 100 hosts, 7 bits must be left for host bits.
Answer:
The characteristic that is violated is Availability.
Explanation:
- The network is passing data at mostly, it means performance is good. Junior network engineer is doing his job well then there is minimum chance of network failure or lack of manageability.
- The scalability; range of computing capabilties can be managed by the engineer.
- However, sometimes the core router might get crashed due to unavailability of the network that is not under the control of the engineer.
Answer:
Write documents consisting mainly of text, Create databases, Create tables for organizing and calculating data, Create presentations to display in front of groups to display data and other info, Create advanced documents such as magazines, flyers, coupons, and other things, Organize your day and easily manage contacts and emails.
