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Ganezh [65]
2 years ago
8

As part of their application for a loan to buy Lakeside Farm, a property they hope to develop as a bed-and-breakfast operation,

the prospective owners have projected:
Monthly fixed cost (loan payment, taxes, insurance, maintenance) $6000
Variable cost per occupied room per night $ 20
Revenue per occupied room per night $ 75
a. Write the expression for total cost per month. Assume 30 days per month.
b. Write the expression for total revenue per month, first using the general variables, and second including the values of known variables).
c. If there are 12 guest rooms available, can they break even? What would be the profit with 12 rooms?
d. What percentage of rooms would need to be occupied, on average, to break even?
Mathematics
1 answer:
Lunna [17]2 years ago
6 0

Answer:

Instructions are below.

Step-by-step explanation:

Giving the following information:

Monthly fixed cost= $6,000

Variable cost per occupied room per night= $20

Revenue per occupied room per night= $75

Fi<u>rst, we need to structure the total cost formula:</u>

Total cost= 6,000 + 20*x

x= occupied room

<u>Now, we can find the expression for total revenue:</u>

Revenue= selling price per unit*units - fixed cost - unitary variable cost*units

Revenue= 75*x - 6,000 - 20*x

<u>I assume that the 12 rooms will be occupied for the 30 days:</u>

Revenue= 75*(12*30) - 6,000 - 20*(12*30)

Revenue= $13,800

<u>Finally, we need to determine the break-even point in units:</u>

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 6,000 / (75 - 20)

Break-even point in units= 109 rooms

On percentage= (109/360)*100= 30.28%

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astra-53 [7]

Answer: (below)

Step-by-step explanation:

The functions shown are exponential functions, which have the form f(x) = a*(b)^x. "a" represents the intial value, while "b" represents the growth factor.

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Now, back to this question, let's look at our functions. In the function on the left, the growth factor is 0.87, which is between 0 and 1, so this function is decaying. For the function on the right, the growth factor is 1.25, which is greater than 1, so this function is decaying. Next, let's look at our graphs. In the left graph, the function is growing, so it matches with the function on the right. Meanwhile, in the right graph, the function is decaying, so it matches with the function on the left.

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