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larisa [96]
3 years ago
10

Type the length of the radius if the diameter is 6 cm

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

3

radius= diameter/2

radius=6/2

radius=3

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Solution -9-8(1+4h)= -17
geniusboy [140]
Step 1. <span>Add </span>9<span> to both sides

</span>-8(1+4h)=-17+9

Step 2. Simplify -17+9 to -8

-8(1+4h)=-8

Step 3. Divide both sides by -8

1+4h=1

Step 4. Cancel 1 on both sides

4h=0
 Step 5. Divide both sides by 4

h=0

Done! :) Hope this helps! :)

To check -9-8(1+4h)=-17 follow these steps below:

Step 1. Let h = 0

-9-8*(1+4*0)=-17

Step 2. Simplify 4 * 0 to 0

-9-8*(1+0)=-17

Step 3. Simplify 1 + 0 to 1

-9-8*1=-17
<span>
Step 4. </span><span>Simplify  8 * 1 to 8
</span>
-9-8=-17
<span>
Step 5. </span><span>Simplify -9 -8 to -17
</span><span>
</span>-17=-17
<span>
Done! :)
 </span>
5 0
3 years ago
Read 2 more answers
PLZ SHOW ALL WORK
lara31 [8.8K]

Part I
We have the size of the sheet of cardboard and we'll use the variable "x" to represent the length of the cuts. For any given cut, the available distance is reduced by twice the length of the cut. So we can create the following equations for length, width, and height.
width:  w = 12 - 2x
length: l = 18 - 2x
height: h = x

Part II
v = l * w * h
v = (18 - 2x)(12 - 2x)x
v = (216 - 36x - 24x + 4x^2)x
v = (216 - 60x + 4x^2)x
v = 216x - 60x^2 + 4x^3
v = 4x^3 - 60x^2 + 216x

Part III
The length of the cut has to be greater than 0 and less than half the length of the smallest dimension of the cardboard (after all, there has to be something left over after cutting out the corners). So 0 < x < 6

Let's try to figure out an x that gives a volume of 224 in^3. Since this is high school math, it's unlikely that you've been taught how to handle cubic equations, so let's instead look at integer values of x. If we use a value of 1, we get a volume of:
v = 4x^3 - 60x^2 + 216x
v = 4*1^3 - 60*1^2 + 216*1
v = 4*1 - 60*1 + 216
v = 4 - 60 + 216
v = 160

Too small, so let's try 2.
v = 4x^3 - 60x^2 + 216x
v = 4*2^3 - 60*2^2 + 216*2
v = 4*8 - 60*4 + 216*2
v = 32 - 240 + 432
v = 224

And that's the desired volume.
So let's choose a value of x=2.
Reason?
It meets the inequality of 0 < x < 6 and it also gives the desired volume of 224 cubic inches.
3 0
3 years ago
True or false?<br> All quadrilaterals are also rhombuses.
Molodets [167]

Answer:

It's false

All quadrilaterals are also rhombus, <u>False</u>

4 0
3 years ago
Read 2 more answers
I need help trying to figure this out I think I have and answer but I want to make sure.
yKpoI14uk [10]

Answer:

34

Step-by-step explanation:

The mean is calculated as

mean = \frac{frequency(midpoint)}{frequency}

let x be the missing frequency, then

Total frequency × midpoint

= (16 × 2) + 7x + (20 × 12) + (10 × 17) = 32 + 7x + 240 + 170 = 442 + 7x

Total frequency = 16 + x + 20 + 10 = 46 + x, thus

\frac{242+7x}{46+x} = 8.5 ( cross- multiply )

442 + 7x = 8.5(46 + x)

442 + 7x = 391 + 8.5x ( subtract 8.5x from both sides )

442 - 1.5x = 391 ( subtract 442 from both sides )

- 1.5x = - 51 ( divide both sides by - 1.5 )

x = 34

The missing frequency is 34

3 0
3 years ago
Jojo likes to paint She estimates the number of paintings she completes using the function P(W) = w – 2. where w is the number o
KATRIN_1 [288]

Answer:

P[J(y)] = 2/3 * J(y) -2

Step-by-step explanation:

4 0
2 years ago
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