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larisa [96]
3 years ago
10

Type the length of the radius if the diameter is 6 cm

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

3

radius= diameter/2

radius=6/2

radius=3

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Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te
Aleonysh [2.5K]

Answer:

t=5.18 minute

Step-by-step explanation:

Using Newton's law of cooling

\frac{dT}{dt}=-k(T-T_{s})

T is temperature of a cup of coffee at any time t T_{s}, is the temperature of the surrounding and k is a constant of proportionality in this negative because temperature is decreasing.

T(0)=190\\T(1)=170\\T_{s}=66

\frac{dT}{dt}=-k(T-T_{s})\\\frac{dT}{(T-T_{s})}=-k*dt\\\int\limits {\frac{1}{T-T_{s} } } \, dT=-\int\limits {k} \, dt\\ln(T-T_{s})=k*t+C\\e*ln(T-T_{s})=e^{k*t+C} \\T-T_{s}=e^{k*t}*e^{C}\\e^{C}=C\\T-T_{s}=e^{k*t}*C\\T=T_{s}+e^{k*t}*C

To find constant knowing the time and the temperature the first step of the change of energy in cup of coffee

T=T_{s} +e^{-k*t}*C\\ C=190-66=124\\170=66+124*e^{-k*2}\\ 170-66=124*e^{-k*2}\\ln(\frac{104}{124})=ln*e^{-k*2}\\-0.175=-k*2\\k=0.08794

Now using the constant of decreasing can find the time to be a 145 temperature the cup of coffee

145=66+124*e^{-k*t} \\145-66=124*^{-0.087*t}

ln(0.637)=ln*e(-0.087*t)\\-0.45=-0.087*t\\t=5.18minutes

4 0
3 years ago
48 is what percent of 120?
Nataliya [291]

Answer:

Step-by-step explanation:

57.6

8 0
2 years ago
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At a water park, 27 out of 90 tickets sold were child tickets. what percentage of the tickets were child tickets?
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You do 27 divided by 90 27/90=0.3 and then move the decimal two places which would give you 30%
3 0
3 years ago
How to solve 2(x+y)^2-9(x+y)-5​
Aliun [14]

Answer:

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⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0

⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0

taking (x + y -5 ) common , 

⇒(x + y -5 )[2(x + y) + 1]  =0 

⇒(x + y -5)(2x + 2y +1) =0

hope , you got this 

6 0
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a woman earned wages of $34,600, received $1500 in interest from savings acxount, and contributed $2900 to a tax-deferred retire
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