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3 years ago

8

Im stuck lol, I'm doing algebra 1, the answer is supposed to be

%20" id="TexFormula1" title="27 \frac{3}{8} " alt="27 \frac{3}{8} " align="absmiddle" class="latex-formula">

1 answer:

maxonik [38]3 years ago

4 0

$27.37

...................

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Zina [86]

Answer:

π(5²)(13)+⅓π(5²)(12)

Step-by-step explanation:

You can find the volume of the cylinder by:

V=πr²h

which is V1=π(5²)(13)

and the volume of the crooked cone by:

⅓πr²h

which is V2=⅓π(5²)(12)

and you need the volume of the whole shape. you can find by adding V1+V2

3 0

1 year ago

A random variable x takes four possible values, 0, 2, a, and b, where a and b are unknown numbers. if pr[x = 0] = 0.2, pr[x=2] =

Alexus [3.1K]

$\displaystyle\sum_{x\in\{0,2,a,b\}}\mathbb P(X=x)=1$
$\mathbb P(X=0)+\mathbb P(X=2)+\mathbb P(X=a)+\mathbb P(X=b)=1$
$0.2+0.4+0.3+\mathbb P(X=b)=1$
$\implies\mathbb P(X=b)=0.1$

$\mathbb E(X)=\displaystyle\sum_{x\in\{0,2,a,b\}}x\mathbb P(X=x)=2.8$
$0\mathbb P(X=0)+2\mathbb P(X=2)+a\mathbb P(X=a)+b\mathbb P(X=b)=2.8$
$0.8+0.3a+0.1b=2.8$
$0.3a+0.1b=2$

$a+b=6\implies0.3a+0.1b=0.2a+0.1(6)=2$
$0.2a+0.6=2\implies0.2a=1.4\implies a=7$

7 0

2 years ago

The sum of 3 times a number and 4 is 9.

larisa [96]

Answer: x = 5/3

Step-by-step explanation:

Let the number be x

Then

3x + 4 = 9

3x = 9-4

3x = 5

x = 5/3

please click thanks and mark brainliest if you like :)

8 0

2 years ago

Read 2 more answers

A farmer plants 987 apple trees in 9 rows. Can each row have the same number of trees? How do you know?

alexira [117]

Answer:

No,

Step-by-step explanation:

each row can not have the same number of trees as the number 987 can not be evenly divided into 9 rows.

6 0

2 years ago

Read 2 more answers

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago