What box plot are you talking about
Im guessing it would be about 50 degrees
Answer: One POSSIBLE answer is (0,9)
Step-by-step explanation: This may look hard but it's actually super easy. All you have to do is substitute a value for x and see what you get as the y value. The first thing I would do is rearrange the equation so that the equation is in the format y = something. So the first thing you should do is subtract 6x from both sides of the equation and you should get -y=-6x+9. Right now, the y is being multiplied by -1, and to undo multiplication, you have to divide. So divide both sides of the equation by -1 (remember, what you do on one side of the equation, YOU HAVE TO DO THE SAME THING ON THE OTHER SIDE). So your new equation would be y=6x-9. Then, all you have to do is substitute a value for x and see what you get for y (x is basically the input and whatever you get for y is the output). S for example, let's say that x=0. So substitute a 0 in the equation wherever you see an x. So in this case, you would get y=(6x0)+9. Then you just simplify. So 6x0 is 0 and 0+9=9 So y=9
TO RECAP: Rearrange the equation so that the equation is in the format y = something. Then, input any number for x, and whatever you get for y is what you put in the brackets as your y value for your final answer.
Hope this helps!
<h3>
Exact Area = 1200 - 300pi square cm</h3><h3>
Approximate Area = 257.522203923062 square cm</h3>
Work Shown:
The area of the rectangle is 40*30 = 1200 square cm
Note how we have 4 circles along the horizontal dimension which is 40 cm, so each diameter is 40/4 = 10 cm, and the radius is 10/2 = 5 cm
Each circle has an area of pi*r^2 = pi*5^2 = 25pi
There are 4*3 = 12 circles, so the circle areas combine to 12*25pi = 300pi
Using a calculator, we find that 1200 - 300pi = 257.522203923062 approximately. Round this however you need to.
Answer:
2 Awnsers
Step-by-step explanation:
Because you need one awnser for interior angle sum and one awnser for exterior angle sum. Lmk if you need me to help figure out the 2 sums :)
