Well as x can never actually be -1 because I'm in the denominator -1 + 1 = 0 and we cannot divide by zero. But we can look at what number it approaches and i assume that is the relative value. sometimes functions will have asymptotes and others will have holes in the graph. this one would have an asymptote going down at a rapid rate. the asymptote would go on forever getting infinitely close to -1 but never touching. So I would say since the asymptote goes down forever that the graph approaches negative infinity
Answer:
Isosceles
Step-by-step explanation:
I'm not 100% sure but i believe its an isosceles.
Answer:
Step-by-step explanation:
Factor all the factors making up the square root.
108: 2*2*3*3*3
a^7: a*a*a*a*a*a*a
b^5:b * b * b * b * b
The rule for taking a square root of this is
For every pair, you get to take one number outside the root sign and throw the other one away.
2*3*a * a * a* b * b√(3*a * b)
6a^3b^2 * √(3*a*b)
Judging by the question you have provided I came to the conclusion that you have already solved your own problem!
If the goal is to find X when X=-15 then your answer for X should be -15!
If this is not the entire equation please post the entire one!
Hope this helped!
-Blake
The number<span> is between integers, so it can't be an integer or a whole </span>number<span>. It's written as a ratio of two integers, so it's a </span>rational number<span> and not irrational. All</span>rational numbers<span> are real </span>numbers<span>, so this </span>number<span> is </span>rational<span> and real.</span>
