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zepelin [54]
3 years ago
11

Marie is saving money for home repairs. To date, she has saved $1,329. She needs at least $1,569 for the repairs. She plans to s

et aside $40 per week to add to her current savings. If this situation is modeled by the inequality below, how many more weeks, x, does she need to continue saving in order to have enough money for the repairs? $1,329 + $40x > $1,569
Mathematics
1 answer:
Roman55 [17]3 years ago
8 0

Answer:

  x > 6

Step-by-step explanation:

Subtract $1329 from both sides, then divide by $40.

  $1,329 + $40x > $1,569

  $40x > $240

  x > 6

Marie needs to save for more than 6 more weeks.

_____

<em>Comment on the answer</em>

The given inequality is written using the > symbol. Marie would have exactly enough to cover the projected cost after 6 weeks, but it is appropriate from a finance point of view for her to save more than the required amount. It will take more than 6 weeks for her to do that.

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Answer:

y = 4x - 12

Step-by-step explanation:

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The figure shown is created by joining three rectangles. Enter the area of the figure, in square centimeters. Round to the neare
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What is 9 copies of 3.65
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3 0
3 years ago
1. Find the Least Common Multiple of these two monomials:<br> See picture
gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

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The prime factors of the second monomial are:

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LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

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\boxed{LCM=120a^4b^7c^5}

The last choice is correct

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3 years ago
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