Answer:
The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.
The first one would be C and the 2nd is A.
So, we need to find how many students voted for Mark, I assume.
So, we need to divide 30 by 5
30 ÷ 5 = 6
So, 3 × 6 =18.
So, Mark received 18 votes
I think this is the answer.
Glad I could help, and good luck!
AnonymousGiantsFan
Those Great Videos [[ YouTube name ]]
We will start with our guess of 12, since 12*2 = 24.
Divide 24 by 12; 24/12=2. Average this answer with our guess: (12+2)/2=7. This is our new guess.
24/7=3.428571429. Average this with our guess of 7: (3.428571429+7)/2=5.214285715. This is our new guess.
24/5.214285715=4.602739726. Averaging with our guess: (4.602739726+5.214285715)/2=4.90851272. New guess!
24/4.90851272=4.889464766. Averaging with our guess: (4.889464766+4.90851272)/2=4.898988743. New guess! You can see as we go through our guesses are closer and closer to the same number...)
24/4.898988743=4.898970228. Averaging: (4.898970228+4.898988743)/2=4.898979486. At this point our answer is the same every time down to the hundred-thousandth. Our estimate to the nearest hundredth would be 4.90.
Answer:
220
Step-by-step explanation:
Now, I'm not sure if 220 is correct, but I'll explain my reasoning.
We know three angles of a triangle add up to 180 degrees.
So, the smaller triangle has 70 degrees and <em>a</em><em> </em>and <em>b</em><em> </em>variables. By virtue, <em>a</em><em> </em>+ <em>b</em><em> </em>+ 70 = 180.
So, <em>a</em><em> </em><em>+</em> <em>b</em><em> </em>= 110.
Likewise, when you look at the whole triangle, 70 degrees is also one of the angles while <em>c</em><em> </em>and <em>d</em><em> </em>are unknown.
So, <em>c</em><em> </em>+ <em>d</em> + 70 = 180.
This means <em>c</em><em> </em>+ <em>d</em><em> </em>= 110.
So, <em>(</em><em>a</em><em> </em>+<em> </em><em>b</em><em> </em>) +<em> </em><em>(</em><em>c</em><em> </em>+<em> </em><em>d</em><em> </em><em>)</em><em> </em><em>=</em><em> </em>
110 + 110 =
220 degrees.
I hope this helps!
