We don’t know the value of the shorter side, so we will categorize it as x. Side 2 is just 4 feet longer than x, so we would add 4 on to it. Side 3 has double the x, so we would multiply it be 2 for 2x, and subtract the 4 feet from it.
Side 1: x
Side 2: x + 4
Side 3: 2x - 4
If the perimeter is 64 feet, then all of the sides have to add up to it. Therefore, first we add all of the side lengths up:
x + x + 4 + 2x - 4 = 4x.
Now we put 4x, the amount of all these sides added up, equal to the perimeter of 64.
4x = 64. Divide both sides by 4 to get x by itself.
x = 16.
Now that we know x is 16, we will substitute it in for all the side lengths’ equations.
We know that Side 1 was just x, so that will be 16. Since Side 2 was 4 more than x, we’d do 16 + 4 = 20. We substitute 16 in for x in Side 3’s equation: 2(16) - 4 = 32 - 4 = 28.
Therefore, the final lengths of all the sides are:
Side 1: 16
Side 2: 20
Side 3: 28
Answer:
it equal 69 is a arat with 24 legs and 5+5=30
Step-by-step explanation:
1.98 x 10^-12 1.98
------------------ = ---------- x 10^-10
3.6 x 10^-2 3.6
=0.55 x 10^-10
=5.5 x 10^-11
