I think its C... but I'm not too sure. I did some research and couldn't find exactly what you were looking for but, I found loopholes and I think since when the cell increases, the surface area does not affect cell divisions steps. Therefore, I don't think it would change any other way...
Answer: Arenite
Explanation:
Arenite can be defined as the sedimentary clastic rock.
It is of the sand grain size.
It also comprises of matrix.
It is a metamorphosed sediment.
Arenite is formed by the erosion of the turbiditic re-deposition of the sands. It belongs to silicatic limestones.
Answer:
C. It is a male with atleast one dominant allele
Explanation:
In the given pedigree, the two normal parents of the generation I have one daughter with the attached earlobe. Since the trait is recessive, the daughter should be homozygous recessive to express the trait. The genotype of the daughter (shaded circle in generation II) is "aa". To have a daughter with "aa" genotype, both the parents should have one copy of "a" allele. So, the genotype of both parents is "Aa".
In generation II, individual A is non-shaded square. Squares represent males in a pedigree. Since its not shaded, it does not have attached earlobe. Both the parents are heterozygous dominant for attached earlobes (Aa x Aa = 1/4 AA : 1/2 Aa : 1/4 aa). The genotype of this individual may be AA or Aa.
The myelin sheath covers most of the axon. It is important because it helps to protect the axon and speed up the neuron firing process by decreasing the amount of time in the axon.
