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jek_recluse [69]
4 years ago
13

Which of the following could be used to evaluate the expression -6 ( 4 2/3) ?

Mathematics
2 answers:
const2013 [10]4 years ago
7 0

Answer:

A. (-6)(4)+(-6)(\frac{2}{3})

Step-by-step explanation:

Given expression,

-6(4\frac{2}{3})

Since, a mixed fraction can be written as the sum of whole number and fraction.

\implies -6(4\frac{2}{3})=-6(4+\frac{2}{3})

Using distributive property,

-6(4\frac{2}{3})=(-6)(4)+(-6)(\frac{2}{3})

Hence,

(-6)(4)+(-6)(\frac{2}{3}) is used to evaluate the expression.

Option 'A' is correct.

algol134 years ago
4 0

-6 (4 2/3)

-6 * (4 + 2/3)

-6 *4 + -6 * 2/3

Choice B

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Answer:

3,312

lets be real who arctually looks at the step by step just use a calculator for this one

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3 years ago
What is the difference between the absolute value of 4 and the absolute value of -3?
larisa86 [58]
Answer:1
Explanation:since the absolute value of -3 is 3 and 4-3=1
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How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

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(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
3 years ago
Which of the following pairs of functions are inverses of each other?
AnnyKZ [126]

Answer:

Step-by-step explanation:

Rearrange each function to solve for x.

Switch x and y,

The resulting equation is the inverse function.

A:

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x = y-5

y = x-5

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g(x) = 5-x ≠ f⁻¹(x)

g(x) is not the inverse of f(x).

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B:

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x = (y+9)/2

y = (x+9)/2

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C:

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D:

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x = 3y - 12

y = 3x - 12

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g(x) is not the inverse of f(x).

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