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vitfil [10]
2 years ago
6

Analyze Mathematical Relationships (1)(F) Suppose the measures of ∠1 and ∠2 are in a 4 ∶ 11 ratio. Find their measures. (Diagram

is not to scale.)
Mathematics
1 answer:
Gekata [30.6K]2 years ago
4 0

If the angles are complementary, we have that:

  • The measure of angle 1 is of 24º.
  • The measure of angle 2 is of 66º.

-----------------

  • If two angles are complementary, the <u>sum of their measures is 90º.</u>
  • In this problem, we suppose that angles 1 and 2 are complementary, thus:

m_1 + m_2 = 90

-----------------

  • The measures of angle 1 and angle 2 are in a 4:11 ratio, thus:

m_1 = \frac{4}{4+11} = \frac{4}{15}(m_1 + m_2)

m_2 = \frac{11}{4+11} = \frac{11}{15}(m_1 + m_2)

-----------------

Considering m_1 + m_2 = 90

m_1 = \frac{4}{15}(m_1 + m_2) = \frac{4}{15} \times 90 = 4 \times 6 = 24

m_2 = \frac{11}{15}(m_1 + m_2) = \frac{11}{15} \times 90 = 11 \times 6 = 66

The measure of angle 1 is of 24º.

The measure of angle 2 is of 66º.

A similar problem is given at brainly.com/question/24738896

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A, E, B, D, C

Step-by-step explanation:

1) 6 is A

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If
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Answer:

-8n + 9

Step-by-step explanation:

Given that,

A = -3n + 2

B = 5n - 7

Before solving you have to know that,

( + ) × ( + ) = ( + )

( - ) × ( - ) = ( + )

( + ) × ( - ) = ( - )

Let us solve now.

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Combine like terms

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Read 2 more answers
Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3
Basile [38]

Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

\displaystyle \rho=\frac{m}{V}

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

m=\rho.V

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3

Calculating:

V=523.6\ cm^3

The mass is:

m=8.09 gr/cm^3 \cdot 523.6\ cm^3

m=4,235.9 gr

The mass of the steel ball is 4,235.9 gr

4 0
3 years ago
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