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vitfil [10]
3 years ago
6

Analyze Mathematical Relationships (1)(F) Suppose the measures of ∠1 and ∠2 are in a 4 ∶ 11 ratio. Find their measures. (Diagram

is not to scale.)
Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0

If the angles are complementary, we have that:

  • The measure of angle 1 is of 24º.
  • The measure of angle 2 is of 66º.

-----------------

  • If two angles are complementary, the <u>sum of their measures is 90º.</u>
  • In this problem, we suppose that angles 1 and 2 are complementary, thus:

m_1 + m_2 = 90

-----------------

  • The measures of angle 1 and angle 2 are in a 4:11 ratio, thus:

m_1 = \frac{4}{4+11} = \frac{4}{15}(m_1 + m_2)

m_2 = \frac{11}{4+11} = \frac{11}{15}(m_1 + m_2)

-----------------

Considering m_1 + m_2 = 90

m_1 = \frac{4}{15}(m_1 + m_2) = \frac{4}{15} \times 90 = 4 \times 6 = 24

m_2 = \frac{11}{15}(m_1 + m_2) = \frac{11}{15} \times 90 = 11 \times 6 = 66

The measure of angle 1 is of 24º.

The measure of angle 2 is of 66º.

A similar problem is given at brainly.com/question/24738896

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VARVARA [1.3K]

Answer:

the answer is y=-1/6x-1

8 0
3 years ago
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It takes 3 hours to paddle a kayak 12 miles downstream and 4 hours for the return trip upstream. Find the rate of the kayak in s
Furkat [3]

The rate of the kayak in still water is 3.5 mph

<h3><u>Solution:</u></h3>

Given that It takes 3 hours to paddle a kayak 12 miles downstream

Distance covered in downstream = 12 miles

Time taken to cover downstream = 3 hours

Also given that it takes 4 hours for the return trip upstream

Distance covered in upstream = 12 miles

Time taken to cover upstream = 4 hours

<em><u>Formula to remember:</u></em>

If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then: Speed downstream = (u + v) km/hr and Speed upstream = (u - v) km/hr

Let the speed of Kayak in still water = x mph

And The speed of current = y mph

For downstream:

Speed downstream = x + y

We know that speed = \frac{distance}{time}

\frac{distance}{time} = x + y

x + y = \frac{12}{3}

x + y = 4  ------ eqn 1

<em><u>For upstream:</u></em>

Speed upstream = x - y

\frac{12}{4} = x - y

x - y = 3 -------- eqn 2

Now let us eqn 1 and eqn 2

Add eqn 1 and eqn 2

x + y + x - y = 4 + 3

2x = 7

x = 3.5

speed of Kayak in still water = x mph  = 3.5 mph

6 0
3 years ago
3 = 2 – x 3 = 2 – 2 – x 3 = –x 2003-03-02-00-00_files/i0110000.jpg –3 = x A. The student incorrectly applied the multiplication
rewona [7]
Answer:
B. The student did not properly apply the addition property to isolate x

Explanation:
When given an equation to solve, always remember that when you do an external operation (add/subtract/multiply a term or divide by a term) on one side of the equation, the same operation should be applied on the other side in order to maintain the equality of the equation.

Now, let's take a look on the steps done:
Step 1:
3 = 2 - x
Step 2:
3 = 2 - 2 - x
Step 3:
3 = -x

Now, note n step 2, the student wanted to get rid of the 2 next to the x, therefore, he subtracted 2. However, the student did not subtract the 2 from the other side of the equation. Since we're taking addition (we're adding a -2), therefore, the student incorrectly applied the addition property to isolate the x.

The correct steps would be as follows:
Step 1:
3 = 2 - x
Step 2:
3 - 2 = 2 - 2 - x
Step 3:
1 = - x

Hope this helps :)
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Answer: 108$

Step-by-step explanation:

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Musya8 [376]

Answer:

h(r) = 6(r+1)+10

Step-by-step explanation:

Just solve for q. Because that's the output. h(r) = q

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