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vampirchik [111]
3 years ago
11

What is the equation of the line, in general from, that passes through the point (-1,-1) and is parallel to the line whose equat

ion is x+y=3
Mathematics
1 answer:
mars1129 [50]3 years ago
7 0
So you have the find the slope of the line first, and the new line is have the same slope since they’re parallel. So to convert the equation to slope intercept form y=mx+b, the equation is now y=-x+3.
So the slope of new line is -1
Now plug in the point because the point is one the line.
-1=(-1)*(-1)+b
-1=1+b
2=b
So the new equation is y=-1x*2
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Read 2 more answers
What is the first step in estimating the quotient 492/50
frutty [35]

Answer:

See below in bold.

Step-by-step explanation:

Round 492 to 500, then

estimate is 500/50 = 10.

3 0
3 years ago
I need help I’m struggling
andrew-mc [135]
All you need for a point to be left unchanged is it being on the line of reflection. (Generally speaking)

The first one is wrong cause you can have a line of reflection anywhere. If the line is horizontal ( x axis) then the slope would be zero. Whereas a line on y axis would be an undefined slope. There are also diagonal lines of reflections which have slopes

I am pretty sure the second one would be correct because, as previously stated, all the line needs to stay in the same place is it being on the line of reflection.

Again, lines of reflection do not have a set slope, a diagonal line of reflection going like / on the chart through the axis could have a slope of one, but it is not needed for the point to remain in the same place

The point does not necessarily need to be on the origin, it can be anywhere on the line of reflection, and if the line of reflection does not pass through the origin, a point on the origin would be moved in a reflection.

I hope this makes sense and helps you out a bit... have a good day
8 0
3 years ago
Can anyone solve this problem please help me
LUCKY_DIMON [66]
(25 x)^{ \frac{1}{2} } = \sqrt{25x} =5 \sqrt{x}
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