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Answer:
We know that, a 'radical equation' is an equation that contains radical expressions, which further are the expressions containing radicals ( square roots and other roots of numbers ).
In order to solve radical equations, we use the rules of exponents and basic algebraic properties.
The common reasoning to use while solving a radical equation is:
1. Isolate the radical expression.
2. Square both sides of the equation to remove radical.
3. After removing the radical, solve the equation to find the unkown variable
4. Check the answer for the errors occurred by removing the radicals.
For e.g.
i.e. ( Adding 3 on both sides )
i.e.
i.e.
i.e. .
So, the solution the the radical equation is x = 64.
Further, we know that an 'extraneous solution' is that root of the radical equation which is not a root of the original equation and is excluded from the domain.
for e.g. Take
i.e.
i.e.
i.e.
i.e.
i.e. x = 0 and x = 5.
Substituting x = 0 in , gives
i.e.
i.e.
, which is not possible.
So, x = 0 is a solution that does not satisfy the equation.
Hence, x = 0 is an extraneous solution.
Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
=
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.