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4 years ago

Nick is designing a toy car. He is picking between 8 different car models

Mathematics

1 answer:

just olya [345]4 years ago

7 0

Answer:

Step-by-step explanation:

No of types of car model = 8

No of color = 10

we can solve this problem by using fundamental principle of counting.

It states that if there are "m" ways to do a thing and there are "n" ways to do other thing then there are "m*n* ways of doing two things together.

For example if there are 3 shirts and 4 pants then there are 3 * 4 different ways to wear combination of shirts and pants.

Similarly in this problem there 8 different car model and 10 different colors hence there are 8 * 10 = 80 different ways to select combination of car model and colors.

Thus there are 80 number of cars Nick could design

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Karla and Isamar are disagreeing over which way the graph of the function ????(x) = |x + 3| is translated relative to

____ [38]

Answer:

Isamar

Step-by-step explanation:

We are given that a function

$g(x)=\mid {x+3}\mid$ is a translation of the graph

$f(x)=\mid x \mid$

Karla believes that the graph of g is '' to the right '' of the graph of f.

Isamar believes that the graph of g is ''to the left'' of the graph f.

When we draw a graph then we can see that

The coordinates of vertex of f are (0,0).

The coordinates of vertex of g(x) are (-3,0).

When x shift 3 units towards left then we get g(x)

Therefore, Isamar is correct.

5 0

3 years ago

Find the equation of the line that is perpendicular to y=1/6x+3 and contains the point (-3,23)

Triss [41]

It would be 1/6x+3(-3,23)

5 0

3 years ago

Topic: Finite Geometric Sums <br> what is the value of ..

kobusy [5.1K]

$\bf \sum\limits_{i=a_1}^{a_n}\ a1\cdot (r)^{n-1}\iff S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\qquad 
\begin{cases}
a_1=\textit{first term}\\
r=\textit{common ratio}\\
n=n^{th}\ term
\end{cases}\\\\
-----------------------------\\\\

\begin{array}{llll}
\sum\limits_{i=1}^{3}\ &4\cdot \left( \frac{1}{2} \right)^{i-1}\\
&\uparrow \quad \uparrow \\
&a_1\quad r
\end{array}\iff S_3=4\left( \cfrac{1-\left( \frac{1}{2} \right)^3}{1-\left( \frac{1}{2} \right)} \right)$

7 0

3 years ago

Given: AP=AQ, BP=BQ, CP=CQ <br><br>Prove: A, B and C are collinear.

meriva

Solution:

Given: In the given figure, where there are pair of Quadrilateral, in which AP=A Q, BP=B Q, C P=C Q .

To Prove : A, B and C are collinear.

Construction: Join AC , the point where it intersects P Q is M.

Proof:

AP=A Q, C P=C Q,

So, the quadrilateral A P C Q is a kite.→→If in a quadrilateral One pair of adjacent sides are equal, then the quadrilateral is a kite.

As we know in a kite Diagonals bisect each other at right angles.

∠AMP=∠A M Q=∠CM P=∠C M Q=90°

Also, BP=B Q, C P=C Q.

So, the quadrilateral B P C Q is a kite.

∠B MP=∠B M Q=∠CM P=∠C M Q=90°

As you can see that , 1. ∠AMP +∠CM P=90°+90°=180°→→Shows Point A and C are in line.------------(1)

2. ∠B MP +∠CM P=90°+90°=180°→→→Shows Point B and C are in line.------------------(2)

Combining (1) and (2),

Shows that point A, B,C lie in a line.

It means Points A, B,C are Collinear.

3 0

3 years ago

A newborn baby has about 26,000,000,000 cells. An adult has about 4.94 x 13 cells. How many times as many cells does an adult ha

finlep [7]

an adult has 4.94 x 10^13 cells = 49,400,000,000,000

49,400,000,000,000 - 26,000,000,000 = 49,374,000,000,000

scientific notation form : 4.9374 x 10^13

3 0

3 years ago