3 years ago

Evaluate

Mathematics

1 answer:

LekaFEV [45]3 years ago

5 0

$\lim_{x\to0^+}\frac{1-\cos(x)}{x^2\sin(x)}=\frac{1-\cos(0^+)}{0^+^2\sin(0^+)\frac{0^+}{+\infty}=\boxed{0^+}$

Hope this helps.

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market price of a dress is 1500 rupees shop owner give a discount of 20% find the discount and the bill amount paid

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3 years ago

What is the volume of the pyramid 7x7x8

dolphi86 [110]

Answer:

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we know that

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Answer:

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