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3 years ago

5

For any positive integer X, let the symbol X, refer to lcm[12,X]. What is the largest value among the numbers 2,4,6,8,10,

and 12*?

1 answer:

babunello [35]3 years ago

6 0

12 since it is greater than the rest of the numbers

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3 years ago

Due tomorrow <br> 3 questions

jasenka [17]

Answer:

7.

green blocks represent n

and normale digits (plus green) are orange

Anne: 1 orange block and increasing 2 green blocks from 2 sides

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9.

a.y = 6x

b.y = 2^x

c.y = x+10

10.

a. 2 green blocks and 2 orange blocks

c. 3 green blocks and 1 orangle blocks

b. 4 green blocks

d.2 green blocks and 1 orange block

Step-by-step explanation:

for 10, it doesn't really matter

8 0

3 years ago

Your task is to build a road joining a ranch to a highway that enables drivers to reach the city in the shortest time. The perpe

lubasha [3.4K]

Answer:

(a)In the attachment

(b)The road of length 35.79 km should be built such that it joins the highway at 19.52km from the perpendicular point P.

Step-by-step explanation:

(a)In the attachment

(b)The distance that enables the driver to reach the city in the shortest time is denoted by the Straight Line RM (from the Ranch to Point M)

First, let us determine length of line RM.

Using Pythagoras theorem

$|RM|^{2}=30^2+x^2\\|RM|=\sqrt{30^2+x^2}$

The Speed limit on the Road is 60 km/h and 110 km/h on the highway.

Time Taken = Distance/Time

Time taken on the road $=\frac{\sqrt{30^2+x^2}}{60}$

Time taken on the highway $=\frac{50-x}{110}$

Total time taken to travel, T $=\frac{\sqrt{30^2+x^2}}{60}+\frac{50-x}{110}$

Minimum time taken occurs when the derivative of T equals 0.

$T^{'}=\frac{x}{60\sqrt{30^2+x^2}}-\frac{1}{110}\\\frac{x}{60\sqrt{30^2+x^2}}-\frac{1}{110}=0\\\frac{x}{60\sqrt{30^2+x^2}}=\frac{1}{110}\\110x=60\sqrt{30^2+x^2}\\$

Square both sides

$12100x^2=3600(30^2+x^2)\\12100x^2=3240000+3600x^2\\12100x^2-3600x^2=3240000\\8500x^2=3240000\\x^2=\frac{3240000}{8500} =381.18\\x=\sqrt{381.18} =19.52$

The road should be built such that it joins the highway at 19.52km from the point P.

In fact,

$|RM|=\sqrt{30^2+19.52^2}=35.79km$

4 0

3 years ago

Gomez found the masses of three rocks for a science project. The first rock had a mass of 19.28 grams the second rock had a mass

shusha [124]

1.72 because rocks 1 and 2 add up to 44.58 46.3-44.58=1.72

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3 years ago

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