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3 years ago

I NEED HELP ASAP Which equation is equivalent to: −10r−6=115

Mathematics

2 answers:

otez555 [7]3 years ago

6 0

Answer:

the correct answer is B

Anna [14]3 years ago

4 0

B is the right answer to this question because you have to change the operator

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Tanmayi wants to raise $175 for a school fundraiser,She has raised $120 so far. How much more does she need to reach her goal?

vampirchik [111]

She needs $55 more dollars

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3 years ago

Baker made 5 pounds of icing. He used 4/9 of the icing to decorate. How much did he have left over?

Elena L [17]

If the baker made 5 pounds of icing and used 4/9 of the icing to make decorations, then he used:

5 * 4/9 =
= 20/9 =
= 2 2/9 [of icing]

To find out how much he has left over, we just need to substract 2 2/9 from 5:

5 - 2 2/9 =
= 3 - 2/9 =
= 2 7/9

Answer: The baker has <u>2 7/9</u> of the icing left.

6 0

3 years ago

Find the LCD to each the fractions and then add them together 1/4 + 2/5 + 1/3

jekas [21]

The LCD of these fractions is 60!

The sum of these fractions is $\frac{59}{60}$ !

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

6 0

3 years ago

Read 2 more answers

Which one is not equal

densk [106]

Answer:

Step-by-step explanation:

hope this helps i took the test

4 0

3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0

2 years ago

Read 2 more answers