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asambeis [7]
3 years ago
11

An object travels back and forth along a straight line. Its velocity, in centimeters per second, is given by the function v(t) =

Equals 13 sine (StartFraction pi Over 45 EndFraction t), where t is time in seconds.
What is the maximum velocity of the object?

0 cm/s
13 cm/s
26 cm/s
90 cm/s

Mathematics
2 answers:
snow_lady [41]3 years ago
7 0

Answer: 13 cm/s , B on Edgenuity

Step-by-step explanation:

natta225 [31]3 years ago
6 0

What is the maximum velocity of the object?

The maximum velocity of the object is 13 cm/s

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Evaluate 2(x - 4) + 3x - x2 for x = 2.<br> O A. -6<br> O B. -2<br> O C. 6<br> O D. 2
Olenka [21]

Answer:

B. -2

Step-by-step explanation:

2(x - 4) + 3x - x2

2(2 - 4) + 3(2) - (2)2

2(-2) + 6 - 4

-4 + 6 - 4

-8 + 6

-2

8 0
3 years ago
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
What’s the value of x
kozerog [31]
Answer should be:

X=9.
6 0
3 years ago
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If the atomic number is 15 how many protons will it have?
andrey2020 [161]
It will have 15 protons because the atomic number will always equal the number of protons and vice versa
6 0
3 years ago
What is 1102 using the polynomial identity (a+b)2=a2+2ab+b2 ?
Virty [35]

Answer:

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Hope this helped!

7 0
2 years ago
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