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nekit [7.7K]
3 years ago
13

{-5x+3y less than or equal to 45{2x +3y>24​

Mathematics
2 answers:
sergey [27]3 years ago
8 0

less than

Step-by-step explanation: so -5 x 3+ -15 so which is less than

Softa [21]3 years ago
6 0

Answer:

7

Step-by-step explanation:

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A boy walks 16 km in 2 days, in how many days will he walk 256km?
Contact [7]

Answer:

32 days

Step-by-step explanation:

2 days = 16km

1 day = 8km

256km÷8km=32 days

4 0
3 years ago
Solve for x.<br> 9/4 x = 8 1/2<br> A) 3 1/8<br> B) 3 7/8<br> C) 19 7/9<br> D) 19 1/8
Wittaler [7]

Answer:

B

Step-by-step explanation:

Because

6 0
3 years ago
Find the equation of the secant line through the points where x has the given values. f(x) = x2 + 2x; x = 4, x = 6
devlian [24]

Answer:

  12x -y = 24

Step-by-step explanation:

You want a line through points (4, f(4)) and (6, f(6)). Evaluating the function, we find the points are (4, 24) and (6, 48). In the 2-point form of the equation for a line, we find ...

  y = (y2 -y1)/(x2 -x1)(x -x1) + y1

  y = (48 -24)/(6 -4)(x -4) +24 . . . . filling in the values

  y = 12(x -4) +24 . . . . . . one form of the equation for the secant

  12x -y = 24 . . . . . . . . . . standard form equation of the line

__

The slope-intercept form of the equation is ...

  y = 12x -24

8 0
3 years ago
In ΔRST, r = 53 inches, ∠S=6° and ∠T=58°. Find the length of s, to the nearest inch.
yaroslaw [1]

Answer:

s = 6 inches

Step-by-step explanation:

Given:

r = 53 inches,

∠S = 6°

∠T = 58°.

Required:

Length of s

Solution:

Use Sine Rule

Thus:

\frac{s}{Sin(S)} = \frac{r}{Sin(R)}

<R = 180 - (58 + 6)

<R = 116°

r = 53 inches,

∠S = 6°

s = ?

Plug in the values

\frac{s}{Sin(6)} = \frac{53}{Sin(116)}

Multiply both sides by Sin(6)

\frac{s}{Sin(6)} \times Sin(6) = \frac{53}{Sin(116)} \times Sin(6)

s = \frac{53 \times Sin(6)}{Sin(116)}

s = 6 inches (nearest inch)

7 0
3 years ago
Suppose u = (1,2,3), v = (2, -3, -4), and w = (1,0,-2). (a) Find u-2v + 3w. (b) Write the vector (3,4,5) as a linear combination
marishachu [46]
<h2>Answer with explanation:</h2>

We are given vectors u,v and w as follows:

      u=(1,2,3)\,\ v=(2,-3,-4),\ and\ w=(1,0,-2)

(a)

Now we are asked to find the value of:

  u-2v+3w

The value is calculated as follows:

u-2v+3w=(1,2,3)-2(2,-3,-4)+3(1,0,-2)\\\\i.e.\\\\u-2v+3w=(1,2,3)+(-2\times 2,-2\times -3,-2\times -4)+(3\times 1,3\times 0,3\times -2)\\\\i.e.\\\\u-2v+3w=(1,2,3)+(-4,6,8)+(3,0,-6)\\\\i.e.\\\\u-2v+3w=(1-4+3,2+6+0,3+8-6)\\\\i.e.\\\\u-2v+3w=(0,8,5)

                              Hence,

                 u-2v+3w=(0,8,5)

(b)

We are asked to represent (3,4,5) as a linear combination of u, v, and w.

Let:

(3,4,5)=au+bv+cw

(3,4,5)=a(1,2,3)+b(2,-3,-4)+c(1,0,-2)

i.e.

(3,4,5)=(a,2a,3a)+(2b,-3b,-4b)+(c,0,-2c)\\\\i.e.\\\\(3,4,5)=(a+2b+c,2a-3b,3a-4b-2c)\\\\i.e.\\\\a+2b+c=3----------(1)

2a-3b=4-------------(2)

3a-4b-2c=5------------(3)

on multiplying equation(1) by 2 an then adding equation (1) to equation (3)

5a=11\\\\i.e.\\\\a=\dfrac{11}{5}

on putting the value of a in equation (2) we get:

2\times \dfrac{11}{5}-3b=4\\\\i.e.\\\\\dfrac{22}{5}-3b=4\\\\i.e.\\\\3b=\dfrac{22}{5}-4\\\\i.e.\\\\3b=\dfrac{2}{5}\\\\i.e.\\\\b=\dfrac{2}{15}

Now on putting the value of a and b in equation (1)

\dfrac{11}{5}+2\times \dfrac{2}{15}+c=3\\\\i.e.\\\\\dfrac{11}{5}+\dfrac{4}{15}+c=3\\\\i.e.\\\\c=3-\dfrac{11}{5}-\dfrac{4}{15}\\\\i.e.\\\\c=\dfrac{3\times 15-11\times 3-4}{15}\\\\i.e.\\\\c=\dfrac{45-33-4}{15}\\\\i.e.\\\\c=\dfrac{8}{15}

Hence, we have:

(3,4,5)=\dfrac{11}{5}(1,2,3)+\dfrac{2}{15}(2,-3,-4)+\dfrac{8}{15}(1,0,-2)\\\\i.e.\\\\(3,4,5)=\dfrac{11}{5}u+\dfrac{2}{15}v+\dfrac{8}{15}w

5 0
4 years ago
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