{-5x+3y less than or equal to 45{2x +3y>24
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The astronomer has to choose 3 star images out of 8.This is a problem of combinations. This can be expressed as 8C3 i.e. combination of 8 objects taken 3 at a time.
This means, if 8 images are nearby the astronomer will have 56 choices <span>of the three stars.</span>
This means, if 8 images are nearby the astronomer will have 56 choices <span>of the three stars.</span>