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notka56 [123]
3 years ago
6

Do the sample standard deviations target the value of the population standard​ deviation? In​ general, do sample standard deviat

ions make good estimators of population standard​ deviations? Why or why​ not?
Mathematics
1 answer:
MArishka [77]3 years ago
6 0

Answer:

If the mean of the sample standard deviations is equal to the population standard​ deviation, then the sample standard deviations target the population standard deviation and are called an unbiased estimator.  

If the mean of the sample standard deviations is not equal to the population standard​ deviation, then the sample standard deviations target the population standard deviation and are called a biased estimator.

A biased estimator regularly underestimates or overestimates the parameter.  

  • An unbiased sample statistics are good​ estimators
  • A biased sample statistics are not good estimators.
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What kind of question will ask us to use this type of format to evaluate the integral instead of doing the regular integral eval
ANEK [815]

Answer:

Great work!

Step-by-step explanation:

These kind of questions are calculated through Riemann Sum. You can evaluate any definite integral using the Riemann Sum. It should be in the following form:

f(x)dx on the interval [a, b], or

\int _a^b\:f\left(x\right)dx

Now f(x) is simply y. Therefore in this example y = x^3 - 6x. We just need the sufficient amount of data to apply the Riemann Sum, including the interval [a, b] that bounds the area, and the the number of rectangles 'n' that we need to use.

Consider an easier approach to this question: (First attachment)

Graph: (Second Attachment)

6 0
3 years ago
An isosceles triangle has a perimeter of 18 cm. Find a function that models its area A in terms of the length of its base b.
IgorLugansk [536]
So.... notice the picture below

now, we know what the "height" or "altitude" is
now, we also know the perimeter is 18cm

so, k + k + b = 18
or 2k + b = 18
thus  \bf k=\cfrac{18-b}{2}

so... one can say that \bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad 
\begin{cases}
b=b
\\\\
h=\sqrt{k^2-\left( \frac{b}{2} \right)^2}
\\\\
h=\sqrt{k^2-\frac{b^2}{4}}\\
--------------\\
k=\frac{18-b}{2}\qquad thus\\
--------------\\
h=\sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}
\end{cases}\\\\
-----------------------------\\\\
A=\cfrac{1}{2}\cdot b\cdot \sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}

and you can simplify it if you wish.. not sure you have to

7 0
3 years ago
Since 1952 the total number of people living in wales has increased by about one eighth.
SVETLANKA909090 [29]
3000000÷1.125=2666666.6667 Round off to 2666667 people. Feel free to correct this if wrong.
3 0
3 years ago
dentify which of these types of sampling is​ used: random,​ systematic, convenience,​ stratified, or cluster. To determine her a
Bess [88]

Answer:

The sampling method used is a stratified sampling method

Step-by-step explanation:

sampling is the selection of a predetermined representative subpopulation from a larger population, to estimate the characteristics of the whole population.

Stratified sampling: Here, the total population are divided into subcategories (strata) before sampling is done. The strata are formed based on some common characteristics. In our example, the times of the day (morning, afternoon and evening) has widely varying atmospheric conditions which will add biases to the measurement of air quality. For example, the air in the morning if compared to the afternoon in an industrial area may be purer because of minimal industrial activity, hence effective comparison will be made by stratification.

6 0
3 years ago
What is the solution to the inequality -6x + 5 > -1
Oksana_A [137]
-6x + 5 > -1
-6x > -1 - 5
-6x > -6
x < -6/-6
x < 1 <===
3 0
3 years ago
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