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notka56 [123]
3 years ago
6

Do the sample standard deviations target the value of the population standard​ deviation? In​ general, do sample standard deviat

ions make good estimators of population standard​ deviations? Why or why​ not?
Mathematics
1 answer:
MArishka [77]3 years ago
6 0

Answer:

If the mean of the sample standard deviations is equal to the population standard​ deviation, then the sample standard deviations target the population standard deviation and are called an unbiased estimator.  

If the mean of the sample standard deviations is not equal to the population standard​ deviation, then the sample standard deviations target the population standard deviation and are called a biased estimator.

A biased estimator regularly underestimates or overestimates the parameter.  

  • An unbiased sample statistics are good​ estimators
  • A biased sample statistics are not good estimators.
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2 years ago
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it takes someone 15 minutes to prepare 3 1/4 cups of juice how many hours would it take to prepare 32 1/2 cups of juice​
wariber [46]

\bf \begin{array}{ccll} minutes&\stackrel{juice}{cups}\\ \cline{1-2} 15&3\frac{1}{4}\\\\ x&32\frac{1}{2} \end{array}\implies \cfrac{15}{x}=\cfrac{3\frac{1}{4}}{32\frac{1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{3\cdot 4+1}{4}}{\frac{32\cdot 2+1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{13}{4}}{\frac{65}{2}}

\bf \cfrac{15}{x}=\cfrac{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{2}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{5}{~~\begin{matrix} 65 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{15}{x}=\cfrac{1}{10}\implies 150=x\leftarrow \begin{array}{llll} \textit{150 minutes or}\\\\ \textit{2 hours and a half} \end{array}

4 0
3 years ago
Will u help me?
sergey [27]

Answer:

Charles practiced for the relay race for D. 9 hours last week.

Step-by-step explanation:

First, I would find the ratios the ratios for converting hurdle to javelin and javelin to relay.

Hurdle : Javelin ; 5 : 1.5

Javelin : Relay ; 2.5 : 5 or  1 : 2

Next, find the factors compared to the original numbers for hurdle to javelin.

15 / 5 = 3

To find the amount of javelin time they did, multiply 1.5 by the factor we got, 3.

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Finally, double 4.5, since Charles does twice as much relay than he does javelin.

4.5 * 2 = 9 hours

3 0
3 years ago
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