Answer:
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It took them 4 days to install 480 chairs which means if they were working at a constant rate they got 120 chairs installed daily. with 360 chairs left that means in 3 days they will finish. so overall, it took the workers 7 days to finish, or a week.
Answer:
y =
x - 12
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = -
x ← is in slope- intercept form
with slope m = -
, c = 0
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
, then
y =
x + c ← is the partial equation
To find c substitute (3, - 8) into the partial equation
- 8 = 4 + c ⇒ c = - 8 - 4 = - 12
y =
x - 12 ← equation of perpendicular line
Answer:
A sample of 1068 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?
We need a sample of n.
n is found when M = 0.03.
We have no prior estimate of
, so we use the worst case scenario, which is 
Then






Rounding up
A sample of 1068 is needed.
Answer:
-15
Step-by-step explanation:
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