Step-by-step explanation and answers:
300 articles at a total cost of $1500:
$1500 / 300 = $5 / article
Sells 260 articles at a price 20% above this ^ price:
20% of $5 is $1, so $5 + $1 = $6
Then he sells 260 articles at the price of ^ $6
260 * $6 = $1560
Each of the remaining articles is sold at a price that's 50% of the 260 he sold.
He sold those for $6, so he would now sell the last 40 for $3
From the remaining 40 articles, he makes 40 * $3, or $120
The shopkeeper made $1560 + $120 = $1680, which is $180 more than he bought them for ($1500)
Therefore, he made a profit percentage of $180 / $1500, (the amount of profit over the amount spent).
He made a profit percentage, compared to the cost price, of 12%.
Are those your only choices?
5x^2-x(x+4)
5x^2-x^2-4x
4x^2-4x is your answer
I think it's d hope it helps
(A) For x representing the cost of one of Tanya's items, her total purchase cost 5x. The cost of one of Tony's items is then (x-1.75) and the total of Tony's purchase is 6(x-1.75). The problem statement tells us these are equal values. Your equation is ...
... 5x = 6(x -1.75)
(B) Subtract 5x, simplify and add the opposite of the constant.
... 5x -5x = 6x -6·1.75 -5x
... 0 = x -10.50
... 10.50 = x
(C) 5x = 5·10.50 = 52.50
... 6(x -1.75) = 6·8.75 = 52.50 . . . . . the two purchases are the same value
(D) The individual cost of Tanya's iterms was $10.50. The individual cost of Tony's items was $8.75.
