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kompoz [17]
3 years ago
8

3 11/16 into a decimal

Mathematics
2 answers:
emmasim [6.3K]3 years ago
5 0

Answer:

3.6875

Step-by-step explanation:

First, let's leave 3 alone since its a whole number. So now we're dividing the actual fraction. Remember that the top dog goes under, which means that the place where the numerator goes is where the dividend should be, and the denominator is where the divisor should be. Add a decimal point and then after that a few zeros to the 11. Divide like a decimal. You should get 0.6875. Now take that 3 that we left alone before and add it, so you should get 3.6875.

Margaret [11]3 years ago
4 0

Answer:

3.6875

Step-by-step explanation:

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3 years ago
After distributing the terms (3x - 7) (2x + 5), you get a new expression of the form
jeka57 [31]
First multiply (3x-7) and (2x+5)
i already did the multiplication so i am writing the answer
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6 0
2 years ago
Write a polynomial FOR<br> A third-degree polynomial with leading coefficient -4
umka2103 [35]

Answer:

-4x^3 + 2x^2-3

Step-by-step explanation:

Degree is the highest exponent on the variable in a polynomial.

A leading coefficient is the first terms coefficient when the polynomial is written in standard form.

To write this polynomial, write -4x^3 as your first term. Its leading coefficient is -4 and it has a degree of 3. Then add whatever terms after it being sure to not add any more with exponent 3 or higher.

Example: -4x^3 + 2x^2-3

4 0
4 years ago
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
blagie [28]

Answer:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

Step-by-step explanation:

For this case we can define the variable of interest amount of Pb209 and for the half life would be given:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

4 0
4 years ago
Solve: -19&lt;3x-4&lt;5<br> (Graphs are in the image)
jasenka [17]

Answer: B (−5 < x < 3)

Steps

−19 < 3x − 4 < 5

−19 < 3x − 4 and 3x − 4 < 5

x > −5 and x < 3

−5 < x < 3

Number Line

−19 < 3x − 4 < 5 : Solution: − 5 < x < 3

[ Interval Notation: (−5, 3)]

If a < u < b then a < u and u < b

−19 < 3x − 4 : x > −5

3x − 4 < 5 : x < 3

Combine the intervals

Merge Overlapping Intervals

And that equals=

−5 < x < 3

3 0
3 years ago
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