By the Pythagorean theorem
.. x = √((2√3)^2 -(√6)^2) = √(12 -6) = √6 . . . . cm
x = √6 cm
C) r = T + 25.3 because you isolate the r variable
5-3^x = -40
subtract 5 from each side to get
-3^x=-45
divide both sides by -1 to make them positive
3^x = 45
need to do the natural logarithm on both sides to remove the variable from the exponent
so ln(3^x) = ln(45)
use logarithm rule to move x out
x ln (3) = ln(45)
dive each term by ln(3) then simplify to get
ln(3)/ln(45)
so x = ln(3)/ln(45) which calculates out to 3.46497352
round off to ten thousandths is 3.4650
3(x+3)-2x
Distribute the 3
3x+9-2x
Combine like terms
x+9
Set equal to zero if you need to do this part
x+9=0
Get x by itself
x=-9
