We have the following functions:
f (x) = x ^ 2 + 1
g (x) = 1 / x
Multiplying we have:
(f * g) (x) = (x ^ 2 + 1) * (1 / x)
Rewriting:
(f * g) (x) = ((x ^ 2 + 1) / x)
Therefore, the domain of the function is given by all the values of x that do not make zero the denominator.
We have then:
All reals except number 0
Answer:
b. all real numbers, except 0
Answer:
Step-by-step explanation:
The diagonals of a rhombus are perpendicular, so ∠AED = 90° and ∠BEC = 90°.
∠DAE = 180° - ∠AED - ∠EDA = 180° - 90° - 35° = 55°
BD is a transversal across parallel sides AD and BC, so ∠EBC = ∠EDA = 35°.
∠BCE = 180° - ∠BEC - ∠EBC = 180° - 90° - 35° = 55°
Answer:
Circumference : 18.84 inches
Radius: 3 inches
Answer: ![3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Work Shown:
![\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E%7B6%7Dy%5E%7B4%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%2B3%7Dy%5E%7B3%2B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%7D%2Ax%5E%7B3%7D%2Ay%5E%7B3%7D%2Ay%5E%7B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B2%2A3%7D%2Ay%5E%7B3%7D%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%7D%2A%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Explanation:
As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.
Let's solve the inequality. Subtract 5 from both sides. The result will be
<span>x ≥ 5. This states, "x is equal to or greater than 5."
</span>
Plot 5 on the number line, using a dark solid dot. Then draw an arrow from that point to the right.