The area of rectangle:
11 ft · 6 ft = 66 ft²
The area of triangle:
6 ft · 4 ft/2 = 6 ft · 2 ft = 12 ft²
The area of the shaded region:
66 ft² - 12 ft² = 54 ft²
520 divided by 5 which is 104 then multiply 104 by 3 since its 3/5 and the answer is 312
Let
x-------> the first number
y-------> the second number
we know that
![x+y=-5 \\ x=-5-y](https://tex.z-dn.net/?f=x%2By%3D-5%20%5C%5C%20x%3D-5-y)
equation 1
![x*y=-90](https://tex.z-dn.net/?f=x%2Ay%3D-90)
equation 2
substitute the equation 1 in equation 2
![[-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0](https://tex.z-dn.net/?f=%5B-5-y%5D%2Ay%3D-90%20%5C%5C%20-5y-%20y%5E%7B2%7D%20%3D-90%20%5C%5C%20y%5E%7B2%7D%20%2B5y-90%3D0)
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are-12.3117.311
Answer:
B
Step-by-step explanation:
It isn't A. A has to be something like y = -x^2 That minus sign directs the parabola downward.
It could be B which is something like y = x^3 - 5
C has an odd number of real roots (5). In other words it crosses the x axis 5 times. So let's make one of these up and graph it
y = (x^2 - 4)(x^2 - 1)(x + 3) Study this for a minute. The leading coefficient of this polynomial is plus 1. There are no negatives in front of the x. The highest degree is x^5. Now here's the key question: on the left side where does the graph start? In Quad three right? It's coming from the lower left. That is exactly what graph C is NOT doing. So for C the graph has a leading coefficient that is less than 0. a<0
Not C.
D is not the answer either. It opens downward and looks like it is something like y = - x^4 + 3x^3 - 2x^2 + 5x - 2
Answer B: