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dalvyx [7]
3 years ago
6

What is the awnser please

Mathematics
1 answer:
Scilla [17]3 years ago
6 0
The root (zero) of this problem is A., x =5 only.
Substitute f(x)=0

0=x^2 - 10x + 25

Solve for x.

x = 5.
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Is 11/20 greater or less than 1/2
inn [45]
Greater. This is because 1/2 x 10/10 = 10/20. 11>10
3 0
3 years ago
Read 2 more answers
What is the answer to 1n-10=5/6-7-1/3n
navik [9.2K]
1*n-10 = (5/6)*n-((1/3)*n)-7 // - (5/6)*n-((1/3)*n)-7

1*n-((5/6)*n)+(1/3)*n-10+7 = 0

n+(-5/6)*n+(1/3)*n-10+7 = 0

1/2*n-3 = 0 // + 3

1/2*n = 3 // : 1/2

n = 3/1/2

n = 6

That's just in case you had to show your work lol^^
3 0
2 years ago
Read 2 more answers
Solve x
d1i1m1o1n [39]

Step-by-step explanation:

x^{2} - 4x - 7 = 0

First, let's move the 7 to the right-hand side so we can determine what constant we'll need on the left-hand side to complete the square:

x^{2} - 4x = 7

From here, since the coefficient of the x term is -4, we know the square will be (x - 2) (since -2 it's half of -4).

To complete this square, we will need to add (-2)^{2} to both sides of the equation:

x^{2} - 4x + (-2)^2 = 7 + ^{-2}

x^{2} - 4x + 4 = 7 + 4

(x - 2)^{2} = 11

Now we can take the square root of both sides to figure out the solutions to x:

x - 2 = \pm \sqrt{11}

x = 2 \pm \sqrt{11}

7 0
3 years ago
Find the equivalent expressions for (2+7)(x+1).
solong [7]
9x1

You would add 2+7 which =9 then x+1 that’s 1 so it would be 9x1
4 0
3 years ago
Need help please don’t know what to do here
kotykmax [81]

Answer:

Down below

Step-by-step explanation:

a. The range of y = sinθ is [-1,1]

b. The period of y = cosθ is 2π

c. The asymptotes of y = tanθ are -π2, π2, πn

d. The amplitude of y = sinθ is 1

e. The period of y = tanθ is π

f. The max value of y = cosθ is 1

4 0
2 years ago
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