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slava [35]
3 years ago
15

Solve for x. -0.7(0.3x - 0.8) = -4.48

Mathematics
1 answer:
marta [7]3 years ago
8 0
Divide both sides by -0.7 to get rid of that pesky thing in the front
0.3x-0.8=6.4
add 0.8 to both sides
0.3x=7.2
divide both sides by 0.3
x=24
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Which fraction is in reduced form? <br> 4/21<br> 42/54 <br> 18/27 <br> 2/10
Sonbull [250]

Answer:

4/21

Step-by-step explanation:

4/21 can't be reduced anymore there is no number that goes into 4 and 21 and divides perfectly.

4/21 = 4/21

42/54 = 21/27 = 7/9

18/27 = 6/9 = 2/3

2/10 = 1/5

3 0
3 years ago
I dont understand this can someone please help me.​
Elan Coil [88]

Answer:

Difference = 2.25°

Step-by-step explanation:

Here we are given that at depth the Temperature T is inversely proportional to the depth x.

T ∝ \frac{1}{x}

T= 4500 \times \frac{1}{x}

Where 4500 is constant

Now we have to find the difference in the temperature at 1200 mts and 3750 mts

1. x=1200

T= 4500 \times \frac{1}{x}

T= 4500 \times \frac{1}{1200}

T= 3.75

2. x=3750

T= 4500 \times \frac{1}{x}

T= 4500 \times \frac{1}{3750}

T=1.2

Hence Difference is

T = 3.75 -1.20

= 2.25

Therefore The difference of the temperature at 1200 mts and 3750 mts is T=2.25°

8 0
4 years ago
What is the greatest common factor of 24s3,12s4, and 18s
ioda
The only number all of these numbers can be divided by is 2. Therefore, the GCF is 2
8 0
4 years ago
Read 2 more answers
PLZ HELP! 10 points
garri49 [273]

Answer:

i believe it is y=4x+1

Step-by-step explanation:

y intercept is 1, slope is up 4 over 1

sorry if im wrong, hope this helps :)

5 0
3 years ago
Find the equation for the plane through the points Po(3,-2,5), Qo(-3,-1,-5), and Ro(0,-4,4) The equation of the plane is Type an
Vedmedyk [2.9K]

Answer:

- 21 x + 24 y + 15 z =120

Step-by-step explanation:

Given that

Po(3,-2,5), Qo (-3,-1,-5), and Ro (0,-4,4) ,These are the point in the space.

We know that equation of a plane is given as

\begin{vmatrix}x-x_1 & y-y_1 &z-z_1 \\ x_2-x_1 & y_2-y_1 &z_2-z_1 \\ x_3-x_1 &y_3-y_1  & z_3-z_1\end{vmatrix}=0\\

\begin{vmatrix}x-0 & y+4 &z-4 \\ 3-0 & -2+4 &5-4 \\ -3-0 &-1+4  & -5-4\end{vmatrix}=0.

\begin{vmatrix}x & y+4 &z-4 \\ 3 & 2 &1 \\ -3 &3  & -9\end{vmatrix}=0.

Now by solving above determinate we get

x( -18 -3 ) -(y+4 ) ( -27 +3 ) + ( z- 4) (9+6) = 0

-21 x +24 y -24 x 4 + 15 z - 24 = 0

- 21 x + 24 y + 15 z -120 = 0

- 21 x + 24 y + 15 z =120

Therefore the equation of the plane will be

- 21 x + 24 y + 15 z =120

6 0
3 years ago
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