Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.
<h3>What is the hang time equation?</h3>
The hang-time of the ball for a player of jump h is given by:
The expression can be simplified as:
For a player that has a hang time of 0.9s, the jump is found as follows:
h = 3.24 feet.
For a player that has a hang time of 0.8s, the jump is found as follows:
h = 2.56 feet.
The difference is given by:
3.24 - 2.56 = 0.68 feet.
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Simply put if Q is between A and M then you just subtract MQ from AM to to get QA
Answer:
2 and 3.
Step-by-step explanation:
1 + 1
Factor out.
2(1)
Multiply.
= 2
1 + 2
Add the terms.
= 3
Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
Based on the given answers, do you possibly mean 100 instead of 102?
If so, you would move the decimal point of 8.4 two places to the right, meaning the answer would be letter D. 840.
