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julia-pushkina [17]
4 years ago
12

Evaluate the following expression. express your answer in simpilest form. 3/16 +5/8×1/2 =

Mathematics
1 answer:
inessss [21]4 years ago
6 0
The answer would be 1/2 and in decimal form it would be 0.5.
You might be interested in
5x^{4}-7x^{3}-5x^{2}+5x+1-0
den301095 [7]

Answer:

5x^4 -7x^3-5x^2+5x+1

Step-by-step explanation:

Hey!

You would just add all the numbers up, and by making sure that you combine all like terms. In this case it is just 1-0 = 1 and so the solution would be the same as your question but with a 1 and you would get rid of the -0.

Hope this helps!

7 0
3 years ago
Can someone help me find the area of the shaded region? is it just the area of the circle?
mr Goodwill [35]
The shaded region is the area of the circle minus the area
of the pentagon.
A circle = pi * r^2
A circle = pi * 15^2
A circle = 706.5 cm^2

A regular pentagon = (a * p)/2 where a is the apothem, p is the perimeter.
The apothem id the perpendicular height from the midpoint of a side to the center of the pentagon.
To find the apothem you have to use a trig ratio.
A pent = (8.3 * 12*5)/2
A pent = 249 cm^2

Shaded region: circle - pentagon 706.5 - 249 = 457.5

5 0
4 years ago
Which sign makes this number sentence true?
Karolina [17]

Answer:

its D

Step-by-step explanation:

8 0
3 years ago
Amy has saved $725 for a new guitar and lessons. Her guitar costs $475 and lessons are $25 per hour. Determine how many lessons
Tamiku [17]
725- 475= $250
250÷25= 10 lessons
7 0
4 years ago
The probability that a randomly-selected U.S. household owns a pet is 0.39. Given that a household owns a pet, the probability t
xeze [42]

Answer:

0.2508

Step-by-step explanation:

The question asks for a conditional probability.

P(a household owns a dog if it owns a pet) = 0.67

Then P(a household does not own a dog if it owns a pet) = 1 - 0.67 = 0.33

P(a household owns a cat if it owns a pet) = 0.24

Then P(a household does not own a cat if it owns a pet) = 1 - 0.24 = 0.76

P(if a household owns a pet but the pet is not a cat or dog) = P(if a household owns a pet, it does not own a cat) × P(if a household owns a pet, it does not own a dog) = 0.33 × 0.76 = 0.2508

5 0
3 years ago
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